Given two points on the line known as (x1,y1) and (x2,y2): slope = y2y1 x2x1 Page 2 2 Example 1 Find the slope of the line that passes through (1,2) and (3,4). Use the slope equation: slope = y2y1 x2x1 Page 3 3 Example 2 Find the slope of the line that passes through (1,2) and (4,1). That's the basic formula but need
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To solve the exercirses which are shown in the figure attached, you must follow the proccedure below:
7) (x)=x³-6x²+8x
(x)=x(x³-6x²+8)
(x)=(x-4)(x-2)x
The lenght is: x
The height is= (x-4)
8) √(2x+8)-6=4
1. You need to clear the variable "x". Then:
√(2x+8)=4+6
√(2x+8)=10
(√2x+8)²=10²
2x+8=100
2x=100-8
x=92/2
x=46
9) l4x+3l=9+2x
1. To solve the left member, you must evaluate two cases: it could be positive,or negative. Then:
2. Negative:
l4x+3l=9+2x
-4x-3=9+2x
-4x-2x=9+3
-6x=12
x=12/-6
x=-2
3. Positive:
l4x+3l=9+2x
4x+3=9+2x
4x-2x=9-3
2x=6
x=6/2
x=3
The standard form of a parabola is
So, if you expand the square, you get
which is the standard form
