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3 years ago

Help please an equation where the slope is 5 and y-intercept is 12.

Mathematics

1 answer:

Lilit [14]3 years ago

7 0

Answer: y = 5x + 12

Step-by-step explanation:

y = mx + b, where m is the slope, and b is the y- intercept, then we plug in:

y = 5x + 12

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John can reach 60 centimeters above the top of his head. If John is 2 meters tall, how high can he reach?

zlopas [31]

He can reach 2.6 meters or 260 centimeters

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3 years ago

Fareed want to add 1/4+5/8

BigorU [14]

Answer:

$\frac{7}{8}$

Step-by-step explanation:

1st you want to find a common denominator. which is 8.

2nd change $\frac{1}{4}$ to $\frac{2}{8}$

3rd you add $\frac{2}{8}$ and $\frac{5}{8}$ together an you get $\frac{7}{8}$

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3 years ago

Use a Double- or Half-Angle Formula to solve the equation in the interval [0, 2π). (Enter your answers as a comma-separated list

lara31 [8.8K]

Sin(2θ)+sin(θ)=0
use double angle formula: sin(2θ)=2sin(θ)cos(θ).
=>
2sin(θ)cos(θ)+sin(θ)=0
factor out sin(θ)
sin(θ)(2cos(θ)+1)=0
by the zero product property,
sin(θ)=0 ...........(a) or
(2cos(θ)+1)=0.....(b)
Solution to (a): θ=k(π)
solution to (b): θ=(2k+1)(π)+/-(π)/3
for k=integer

For [0,2π), this translates to:
{0, 2π/3,π,4π/3}

8 0

3 years ago

Write an algebraic expression that represent the sum of 8 and two-third of x?

lesantik [10]

We have to sum 8 and two-third of x, so we must multiply x by 2/3 and sum it with 8,

thus, the expression is

$\frac{2}{3}x+8$

3 0

11 months ago

X-y=6 2x-3z=16 2y+z=4 Solve the systems of equations.

Neko [114]

Answer:

Given System of equation:

x-y =6 .....,[1]

2x-3z = 16 ......[2]

2y+z = 4 .......[3]

Rewrite the equation [1] as

y = x - 6 .......[4]

Substitute the value of [4] in [3], we get

$2(x-6)+z = 4$

Using distributive property on LHS ( i.e, $a \cdot (b+c) =a \cdot b+ b \cdot c$ )

then, we have

2x - 12 +z =4

Add 12 to both sides of an equation:

2x-12+z+12=4+12

Simplify:

2x +z = 16 .......[5]

On substituting equation [2] in [5] we get;

2x+z=2x -3z

z = -3z

Add 3z both sides of an equation:

z+3z = -3z+3z

4z = 0

Simplify:

z = 0

Substitute the value of z = 0 in [2] to solve for x;

$2x-3(0) = 16$

2x = 16

Divide by 2 both sides of an equation:

$\frac{2x}{2} =\frac{16}{2}$

Simplify:

x= 8

Substitute the value of x =8 in equation [4] to solve for y;

y = 8-6 = 2

y = 2

Therefore, the solution for the given system of equation is; x = 8 , y = 2 and z =0

5 0

3 years ago