The volume of a sphere is (4/3) (pi) (radius cubed).
The volume of one sphere divided by the volume of another one is
(4/3) (pi) (radius-A)³ / (4/3) (pi) (radius-B)³
Divide top and bottom by (4/3) (pi) and you have (radius-A)³ / (radius-B)³
and that's exactly the same as
( radius-A / radius-B ) cubed.
I went through all of that to show you that the ratio of the volumes of two spheres
is the cube of the ratio of their radii.
Earth radius = 6,371 km
Pluto radius = 1,161 km
Ratio of their radii = (6,371 km) / (1,161 km)
Ratio of their volumes = ( 6,371 / 1,161 ) cubed = about <u>165.2</u>
Note:
I don't like the language of the question where it asks "How many spheres...".
This seems to be asking how many solid cue balls the size of Pluto could be
packed into a shell the size of the Earth, and that's not a simple solution.
The solution I have here is simply the ratio of volumes ... how many Plutos
can fit into a hollow Earth if the Plutos are melted and poured into the shell.
That's a different question, and a lot easier than dealing with solid cue balls.
Divide 50 by 22: 2.27272727...
Round up to hundredth and your final answer is 2.27
hope that helps :)
For full circle area is π * R² [here R = radius],
for a sector of circle with angle β, area will be = (β/2) * R², β is in radian,
here let β = 22.5° = (π * 22.5/180) = π/8 radian,
now [(π/8)/2] * R² = 9π, [π/16] * R² = 9π
R² = 9 * 16 = 144,
R = √144 = 12 m
Answer:
The answer is c
Step-by-step explanation:
Company a = 22 + 0.07m
company b = 8 + 0.12m
We are looking for the time when the prices are equal. i.e. the price of company a = the price of company b
company a = company b
22 + 0.07m = 8 + 0.12m
22 - 8 = 0.12m - 0.07m
14 = 0.05m
m = 14/0.05
m = 280
Therefore, the two companies will cost the same if you talk for 280 minutes
