This might have your answer, I'm so sorry if I'm wrong.
The equivalent value of the sum for any value of "x" is 12x - 6
<h3>How to find the sum of functions?</h3>
Given the sum of the expression as:
3
∑ k(2x-1)
k=0
We need to take the sum of the function at the point where k = 0 to 3
3
∑ k(2x-1) = 0(2x-1) + 1(2x - 1) + 2(2x-1) + 3(2x - 1)
k=0
3
∑ k(2x-1) = 2x-1+4x-2+6x-3
k=0
3
∑ k(2x-1) = 12x - 6
k=0
Hence the equivalent value of the sum for any value of "x" is 12x - 6
Learn more on sum functions here: brainly.com/question/24295771
I beilieve it’s 11 I’m not 100% certain though
A(n)=4+4(n-1)
a(n)=4+4n-4
a(n)=4n
76=4n
n=19
The sum of any arithmetic sequence (series are infinite) is:
(a+a(n))(n/2)
The average of the first and last terms times the number of terms, in this case we found that n=19 so:
19(4+76)/2=760
F(t) = P.e^(r.t) [ and not as you wrote it f(t)+Pe^rt]
plug in:
f(t) = 8.e^(0.08t) (where e = 2.718 and t=8 given, f(8))
f(8) = 8.(2.718)^(0.08*8) = 21.74^(0.64)
f(8) = 7.17
