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dimulka [17.4K]
3 years ago
8

Graphing Trigonometric Functions

Mathematics
1 answer:
Alina [70]3 years ago
8 0

Answer:

hard, search on internet as I don't know this

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Solve the equation 4y-2=26 A y=7 B y=6 C y=3 D Y=26
Lady_Fox [76]
If 4y-2=26  then  4y=26+2
4y=28  divide both side by 4
y=28/4=7   opt A
6 0
4 years ago
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Ruby uses 1/4 yard of ribbon to make 2 bows.Which expression shows the length of ribbon in each bow?
allochka39001 [22]
What you can do in this case is a rule of three to determine the length of each bow.
 We have then:
 1/4 ---> 2
 x ------> 1
 Clearing x we have:
 x = (1/2) * (1/4)
 x = 1/8
 Answer:
 the length of ribbon in each bow is
 x = 1/8
 Equivalently:
 x = (1/4) / 2
 Option 3
3 0
3 years ago
$8.00 divided by 1/4
vazorg [7]

The answer is 32, because when you divide by a fraction you have to multiply the number by it's reciprocal.

5 0
3 years ago
The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of
SCORPION-xisa [38]

Answer:

a) 51.60% probability that in a given year there will be less than 21 earthquakes.

b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 4.5

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.8}{4.5}

Z = 0.04

Z = 0.04 has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 20.8}{4.5}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 20.8}{4.5}

Z = -0.62

Z = -0.62 has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

5 0
3 years ago
Which of the following represents "the difference between a number and eight is twenty-two"?
azamat
Both of the first 8 - N = 22 N - 8 = 22 Represent the difference between a number and 8 is 22 as it is not mentioned that either 8 or the unknown number N is greater so both of the first two represent the difference between a number and 8 is twenty two.
4 0
3 years ago
Read 2 more answers
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