Reflection across y=x is a special case transformation

The original triangle has vertices A(-5,1), B(-4,3), C(-2,1), D(-3,-1) so the transformed triangle has vertices
A'(1,-5), B'(3,-4), C'(1,-2), D'(-1,-3)
Choice A'(1,-5)
From the description we can infer that we have the expression:

.
Now, to write our expression as a as a root, we are going to apply the law of exponents:

first

Next, we are going to apply the law about fractional exponents:
![x^{ \frac{m}{n}}= \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7B%20%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20%20)
![\frac{1}{41^{ \frac{2}{5} }}= \frac{1}{ \sqrt[5]{41^2} }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B41%5E%7B%20%5Cfrac%7B2%7D%7B5%7D%20%7D%7D%3D%20%5Cfrac%7B1%7D%7B%20%5Csqrt%5B5%5D%7B41%5E2%7D%20%7D%20)
We can conclude that the
value of B is 2.
D. Because 5 and 5 could land on any
Thank youuuuuuuuuuuuuuuuuu
Answer:
66
Step-by-step explanation:
Use the formula for the mean of a set of numbers:
sum of the numbers
average = --------------------------------
count of numbers
Here we know that the average mark was 68, so we can write:
75 + 62 + 84 + 53 + x
average = 68 = ----------------------------------
5
or 274 + x
68 = -------------------
5
Solving for x, we multiply both sides by 5: 340 = 274 + x.
Subtracting 274 from both sides effectively isolates x:
340 = 274 + x
- 274 -274
------------------------
66 = x
The fifth student's mark was 66.