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Gennadij [26K]
3 years ago
11

A bag contains 2 red checkers and 6 black checkers. a checker is selected, kept out of the bag, and then another checker is sele

cted. what is p(black, then red)?
Mathematics
2 answers:
yKpoI14uk [10]3 years ago
5 0
Total checkers = 2 + 6 = 8
P(black, then red) = (6/8)(2/7) = 3/14

Answer: 3/14
zvonat [6]3 years ago
5 0

A bag contains 2 red checkers and 6 black checkers. a checker is selected, kept out of the bag, and then another checker is selected.

Total checkers = 2 red + 6 black = 8 checkers

p(black, then red)

Probability ( selecting checker) = \frac{numbe of selected checker }{total checkers}

P( black) = \frac{6}{8}

1 black is selected so remaining 7 checkers

P( red) = \frac{2}{7}

p(black, then red) =\frac{6}{8} * \frac{2}{7}

= \frac{12}{56}

Divide numerator and denominator by 4

So P(black, then red) =\frac{3}{14}

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