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vampirchik [111]
3 years ago
15

4x+10=x+20 whaT WOULD BE THE ANSWER

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
5 0

Answer: that is impossible

Step-by-step explanation:

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An artist created a statue in the shape of a triangular pyramid. The triangular base has a height of 9 feet and base of 16ft. De
MatroZZZ [7]
The volume is 240ft^3. v=Ah/3. v=(72)(10)/3. v=720/3. v=240.
6 0
3 years ago
Find the equation of the line that goes through the point ( 6, 5) and has a slope of 1/3
PSYCHO15rus [73]

Answer (<u>assuming it can be slope-intercept form)</u>:

y = \frac{1}{3} x +3

Step-by-step explanation:

Since we already know a point the line intersects and its slope, we can use the point-slope formula y-y_1 = m (x-x_1) to write an equation, then convert it to slope-intercept form.

Substitute values for m, x_1, and y_1. Since m represents the slope, substitute \frac{1}{3} in its place. Since x_1 and y_1 represent the x and y values of one point the line intersects, use the x and y values of (6,5) and substitute them into the equation. Substitute 6 for x_1 and 5 for y_1. Then, isolate y to put it into slope-intercept form and find an answer:

y -5 = \frac{1}{3} (x-6)\\y-5 = \frac{1}{3}x-2\\y = \frac{1}{3} x+3

7 0
3 years ago
If f(x) = 6x-4, what is f(x) when x = 8
NARA [144]

Answer:

The correct answer is 44

Step-by-step explanation:

6(8)-4

48-4

44

5 0
4 years ago
Read 2 more answers
I need help plotting this on number line
Juli2301 [7.4K]

Answer:

I don't understand this question

8 0
3 years ago
Read 2 more answers
Let
Digiron [165]

What I gather from the question is that X has second moment E(X^2)=81 and variance V(X) = 58, and you're asked to find the expectation and variance of the random variable Y=2X+10.

From the given second moment and variance, we find the expectation of X :

V(X) = E(X^2) - E(X)^2 \implies E(X) = \sqrt{E(X^2) - V(X)} = \sqrt{23}

Expectation is linear, so

E(Y) = E(2X+10) = 2 E(X) + 10 = \boxed{2\sqrt{23} + 10}

Using the same variance identity, we have

V(Y) = V(2X+10) = E((2X+10)^2) - E(2X+10)^2

and

E((2X+10)^2) = E(4X^2 + 40X + 100) = 4E(X^2) + 40E(X) + 100 = 424 + 40\sqrt{23}

so that

V(Y) = V(2X+10) = (424 + 40\sqrt{23}) - (2\sqrt{23} + 10)^2 = \boxed{232}

Alternatively, we can use the identity

V(aX+b) = a^2 V(X) \implies V(2X+10) = 4V(X) = 232

5 0
2 years ago
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