Question

Help for this question pls :)

Answer 1

Step-by-step explanation:

tan(A/2)

tan(A/2)=sinA/1+cos A

tan(A/2)= 5/13÷1+12/13

tanA/2=1/5

Answer 2

Answer:

tan($\frac{A}{2}$ ) = ± $\frac{1}{5}$

Step-by-step explanation:

Using the trigonometric identity

tan ($\frac{A}{2}$ ) = ± $\sqrt{\frac{1-cosA}{1+cosA} }$

Given

tanA = $\frac{5}{12}$ = $\frac{opposite}{adjacent}$

This is a right triangle 5- 12- 13 ( with hypotenuse 13 ), then

cosA = $\frac{adjacent}{hypotenuse}$ = $\frac{12}{13}$ , then

tan ($\frac{A}{2}$ )

= ± $\sqrt{\frac{1-\frac{12}{13} }{1+\frac{12}{13} } }$

= ± $\sqrt{\frac{\frac{1}{13} }{\frac{25}{13} } }$

= ± $\sqrt{\frac{1}{25} }$

= ± $\frac{1}{5}$