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anygoal [31]
3 years ago
8

What is 63×.04 as a decimal

Mathematics
1 answer:
liraira [26]3 years ago
3 0

63 x .04 = 2.52

That is your answer to the question! Hope I helped :)

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A piece of tile is 4 1/2 inches long and 3 1/4 inches wide. What is the area of the tile? A.7 3/4 B.12 C.12 1/8 D.14 5/8
Komok [63]

4 x 2 over 2

8/2 + 1/2 = 9/2

3 x 4 over 4

12/4 +1/4 = 13/4

Top times top over bottom times bottom.

9 x 13 over 2 x 4

117 / 8

14 and 5/8


7 0
3 years ago
FIND THE AREA OF THE RECTANGLE!!!!!!!!
Alex Ar [27]
2-5 x 1/2 = 0.2 (Length x Width)
7 0
4 years ago
Read 2 more answers
What is the simplest form of 34/42
vfiekz [6]
17/21 you just have to find the highest common factor, which in this case, is two
7 0
3 years ago
Read 2 more answers
Need an answer thanks in advance​!
slamgirl [31]

Answer:

1806 seats.

Step-by-step explanation:

From the question given above, the following data were obtained:

Row 1 = 24 seats

Row 2 = 27 seats

Row 3 = 30 seats

Total roll = 28

Total number of seat =?

From the above data, we can liken the roll to be in arithmetic progress.

Also, we are asked to determine the total number of seats in the theater.

Thus the sum of the sequence can be written as:

Roll 1 + Roll 2 + Roll 3 +... + Roll 28 i.e

24 + 27 + 30 +...

Thus, we can obtain obtained the total number of seats in the theater by applying the sum of arithmetic progress formula. This can be obtained as follow:

First term (a) = 24

Common difference (d) = 2nd term – 1st term

Common difference (d) = 27 – 24 = 3

Number of term (n) = 28

Sum of the 28th term (S₂₈) =?

Sₙ = n/2 [2a + (n –1)d]

S₂₈ = 28/2 [2×24 + (28 –1)3]

S₂₈ = 14 [48 + 27×3]

S₂₈ = 14 [48 + 81]

S₂₈ = 14 [129]

S₂₈ = 1806

Thus, the number of seats in the theater is 1806.

6 0
3 years ago
Draw fraction rectangles on dot paper to solve the problems.
juin [17]

Answer:

1) \frac{7}{20}

2) 1\frac{1}{12}

3) \frac{7}{8}

Step-by-step explanation:

1) Given problem,

\frac{3}{5}-\frac{1}{4}

LCM(5,4) = 20,

\frac{3}{5}=\frac{3\times 4}{5\times 4}=\frac{12}{20}

\frac{1}{4}=\frac{1\times 5}{4\times 5}=\frac{5}{20}

\implies \frac{3}{5}-\frac{1}{4}=\frac{12}{20}-\frac{5}{20}=\frac{7}{20}

2) Given problem,

\frac{5}{6}+\frac{1}{4}

LCM(6, 4) = 12,

\frac{5}{6}=\frac{5\times 2}{6\times 2}=\frac{10}{12}

\frac{1}{4}=\frac{1\times 3}{4\times 3}=\frac{3}{12}

\implies \frac{5}{6}+\frac{1}{4}=\frac{10}{12}+\frac{3}{12}=\frac{13}{12}=1\frac{1}{12}

3) ∵ Pizza ate by Manny = \frac{1}{4}

Pizza ate by Frank = \farc{5}{8}

∴ Total pizza eaten = \frac{1}{4}+\frac{5}{8}

LCM(4, 8) = 8,

\frac{1}{4}=\frac{2}{8}

Thus, total pizza eaten =  \frac{2}{8}+\frac{5}{8}=\frac{7}{8}

6 0
3 years ago
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