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LuckyWell [14K]
3 years ago
12

I could probably answer this my self but Whats 9/13 simplifed?

Mathematics
1 answer:
Luda [366]3 years ago
8 0

Answer:

It is simplified

Step-by-step explanation:

13 cant go into any other number.

I hope this helps and have a great day! :)

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This table displays the height of a balloon as it floats away.
kondor19780726 [428]

Answer:

The rate of change is 9.5 ft/min

Step-by-step explanation:

every minute the balloon rises in 9.5 feet increments

7 0
3 years ago
Read 2 more answers
How do you solve this system of equations?<br><br> 18x^2+12xy-18y^2=30<br> -x^2-3xy+y^2=3
kiruha [24]
Combine the like terms.

6 0
4 years ago
Given the following null and alternative hypotheses H0: μ1 ≥ μ2 HA: μ1 &lt; μ2 Together with the following sample information (s
zvonat [6]

Answer:

Null hypothesis: \mu_1 \geq \mu_2

Alternative hypothesis: \mu_1

t=-1.329

p_v =P(t_{30}

With the p value obtained and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the mena of the group 1 is significantly lower than the mean for the group 2.  

Step-by-step explanation:

When we have two independnet samples from two normal distributions with equal variances we are assuming that

\sigma^2_1 =\sigma^2_2 =\sigma^2

And the statistic is given by this formula:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}}+\frac{1}{n_2}}

Where t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

This last one is an unbiased estimator of the common variance \simga^2

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \geq \mu_2

Alternative hypothesis: \mu_1

Or equivalently:

Null hypothesis: \mu_1 - \mu_2 \geq 0

Alternative hypothesis: \mu_1 -\mu_2

Our notation on this case :

n_1 =14 represent the sample size for group 1

n_2 =18 represent the sample size for group 2

\bar X_1 =565 represent the sample mean for the group 1

\bar X_2 =578 represent the sample mean for the group 2

s_1=28.9 represent the sample standard deviation for group 1

s_2=26.3 represent the sample standard deviation for group 2

First we can begin finding the pooled variance:

\S^2_p =\frac{(14-1)(28.9)^2 +(18 -1)(26.3)^2}{14 +18 -2}=753.882

And the deviation would be just the square root of the variance:

S_p=27.457

And now we can calculate the statistic:

t=\frac{(565 -578)-(0)}{27.457\sqrt{\frac{1}{14}}+\frac{1}{18}}=-1.329

Now we can calculate the degrees of freedom given by:

df=14+18-2=30

And now we can calculate the p value using the altenative hypothesis:

p_v =P(t_{30}

So with the p value obtained and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 10% of significance the mena of the group 1 is significantly lower than the mean for the group 2.  

7 0
3 years ago
2.1 ÷ 1.488 rounded to the nearest tenth, I will Give you 20 Points
Sauron [17]
If you were to divide 2.1 by 1.488 you would get a answer such as 1.41129....
If the number is above 5, you round to the next highest number.
If the number is 4 and below, you don’t round to the next highest number.
Since 1.41 has a number below 4 that you have to round, the nearest tenth would stay 4.
meaning the answer is 1.4
5 0
4 years ago
I rlly need help with this if you answer correctly I'll mark you as brainliest so pls answer correctly pls and ty​
Agata [3.3K]
A
for the first because the scatter point is going up in a positive slope so I’m assuming that’s what positive correlation means.. as the dinosaurs length increases the weight increases


B
For the second one , if you plot the dots there’s no relationship .. they’re all over the place
8 0
3 years ago
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