Answer:
The zeros of f(x) are -3, 2 , 6
Step-by-step explanation:
f(x) is a polynomial of degree 3.
If the polynomial is not factorized we will either factorize to find the zero or use trial and error method.
Since the f(x) in the question is in the factorized form. we will have to equate each factor to zero.
f(x) = (x+3)(x-2)(x-6)
x + 3 = 0 => x = -3
x - 2 = 0 => x = 2
x - 6 = 0 => x = 6
The function and the first value stated for x are confusing.
Doing some research, I found that the problem is to evaluate the function

for x = - 1 and x 2.
The solution is:
1) For x = - 1

2) For x = 2
<u>Answer:</u>
x = ±5
<u>Step-by-step explanation:</u>
We are given the following polynomial function and we are to find all of its real roots:

Let
so we can now write it as:

Factorizing it to get:



Substitute back
to get:

The quadratic factor has only complex roots. Therefore, the real roots are x = ±5.
Y = 3x
so
if x = 5 then y = 15
if x = 10 then y = 30
so a = 10 and b = 15
answer is B. second choice
a = 10 and b = 15
For the lunch it would be 20$