Answer:
We accept H₀
Step-by-step explanation:
Normal Distribution
size sample n = 69
sample mean 18.94
standard deviation 8.3
Is a one tailed-test to the left we are traying of find out is we have enough evidence to say that the mean is less than 20 min.
1.-Test hypothesis H₀ ⇒ μ₀ = 20
Alternative hypothesis Hₐ ⇒ μ₀ < 20
2.- Critical value
for α = 0.1 we find from z Table
z(c) = - 1.28
3.-We compute z(s)
z(s) = [ ( μ - μ₀ ) / (σ/√n) ⇒ z(s) = [( 18.94 - 20 )*√69)/8.3]
z(s) = ( -1.06)*8.31/8.3
z(s) = - 1.061
4.- We compare
z(c) and z(s) -1.28 > -1.061
Then z(c) > z(s)
z(s) in inside acceptance region so we accept H₀
I would write the missing variable as x. It's what everyone uses.
Anyway, 91 divided by x is 65.
The way we can do this is reverse 65 and x.
91 divided by 65 = x.
91 divided by 1.4 = 65
65 x 1.4 = 91
x (or ?) = 1.4
Answer:
535.9 ft²
Step-by-step explanation:
Since there are 360° in a circle, and 240° is 2/3 of 360°, we can say that the area of the bolded sector is <em>2/3 the area of the whole circle</em>. The area of a circle with a radius of r is πr², or approximately 3.14r², so the area of the whole circle is ≈ 3.14(16)² = 3.14(256) = 803.84 ft². Taking 2/3 of this gets us 803.84 * (2/3) ≈ 535.9 ft²
b r = 178 + h;
b r + h = 676;
then, 178 + 2h = 676 => h = 498/2 = 249 => b r = 178 + 249 = 427
Answer:
676
Step-by-step explanation:
h=b+178=427
b=b=249
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(b+178)+b=676
2b+178=676
2b=498
b=249
-------------
249+427=676
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