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3 years ago

Which of the following are examples of exponential decay? Select all that apply.

Mathematics

2 answers:

Naddika [18.5K]3 years ago

5 0

Answer:

Exponential decay is the decrease in quantity

The ones that are correct are:

1 (depreciates means diminish or decrease)

Eduardwww [97]3 years ago

3 0

Answer:A,D,F,G

Step-by-step explanation:

All of these say either decrease, depreciate, or decay which all mean exponential decay

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A bag contains 30 red and blue marbles. If 19 are blue, what fraction of the marbles are blue?

Musya8 [376]

Answer:

19%

Step-by-step explanation:

19/100. i don't think it is that simple, but i did the best i could

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3 years ago

in 1990, the value of a home is $170,000. Since then, its value has increased 5% per year. what is the approximate value of a ho

Gwar [14]

value of home in 1991= 105% of 170000

value of home in 1992= 105%×105% of 170000

value of home in 1993= 105%×105%×105% of 170000

=$196,796.25

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4 years ago

What is the degree of each polynomial?

Lana71 [14]

(1) Degree 4 (x^4)

(2) Degree 7 (x^7)

(3) Degree 5 (x^2y^3)

(4) Degree 4 (x^4)

(5) Degree 2 (x^2)

(6) Degree 7 (x^7)

5 0

3 years ago

Read 2 more answers

A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d

Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

force = 4lb
direction = 4, -2
displacement = 7ft
direction = (0, 4) to (5,1)

The unit vector of the force is

$\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}$

$\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }$

The net force acting on the object is

$F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )$

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

$\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}$

$\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }$

The net displacement will be

$7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}$

The work done will be F.d

$w = f. d \\$

$w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs$

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

#SPJ1

6 0

3 years ago

A migraine sufferer took Two 400mg doses of naproxen. The half-life for

12345 [234]

Answer:

If y(t) is the mass (in mg) remaining after t years, then y(t) = y(0) (0.5)^{t/T} = 400 (0.5)^{t /4}, where T is the half-life period and y(0) is the amount at t = 0 years (initial).

Then at t = 20:

y(20) = 400 (0.5)^{20 /4} = \text{12.5 mg}

Step-by-step explanation:

7 0

3 years ago