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Aleksandr-060686 [28]

2 years ago

12

The radius of a cylindrical gift box is (3x + 1) inches. The height of the gift box is three times the radius What is the surfac

e area of the cylinder? Write your answer
as a polynomial in standard form.

1 answer:

ale4655 [162]2 years ago

8 0

I don’t know bc i am trying to get answers to my stuff

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Work out the value of each expression, when r= 2.5 and t = 6.

Usimov [2.4K]

Answer:

a) 4(t - r) = 4(6 - 2.5) = 4 x 3.5 = 14

b) 4t - r = (4 x 6) - 2.5 = 24 - 2.5 = 21.5

c) 2(3t - 10) = 2(3 x 6 - 10) = 2(18 - 10) = 2 x 8 = 16

d) (t - 2)² = (6 - 2)² = 4² = 4 x 4 = 16

e) cannot decipher the equation

f) 6r + t = 6 x 2.5 + 6 = 15 + 6 = 21

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2 years ago

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What is the vertical component of a 100 pound force applied at 30° above the horizontal?

lutik1710 [3]

That would be 100 * sin 30 = 100 * 0.5 = 50 pounds

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2 years ago

Find the sum of the smallest 7- digit number and largest 4-digit number

Snowcat [4.5K]

1009999

Hope it helps you...

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3 years ago

The equation 6y = 30 - 8x has solutions of (b, 1) and (a, b).<br> What are the values of a and b?

victus00 [196]

The values of $a$ and $b$ are $a = \frac{3}{2}$ and $b = 3$ , respectively.

In this question we need to solve the linear equation for each point, first for $(x,y) = (b, 1)$ and later for $(x,y) = (a, b)$ .

If we know that $(x,y) = (b, 1)$ , then the value of $b$ is:

$6 = 30-8\cdot b$

$8\cdot b = 24$

$b = 3$

If we know that $(x,y) = (a, b)$ and $b = 3$ , then the value of $a$ is:

$6\cdot b = 30 - 8\cdot a$

$18 = 30-8\cdot a$

$12 = 8\cdot a$

$a = \frac{3}{2}$

The values of $a$ and $b$ are $a = \frac{3}{2}$ and $b = 3$ , respectively.

To learn more on linear functions, we kindly invite to check this question: brainly.com/question/5101300

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2 years ago

The vertical asymptote of the function f(x) = 3 log(x + 3)

ipn [44]

A function has a vertical asymptote where it is not defined, and the logarithm is defined only if its argument is strictly positive: it has a vertical asymptote if its argument is zero, and is not defined if its argument is negative.

So, you have a vertical asymptote where

$x+3=0 \iff x=-3$

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2 years ago