P^8 • p^−3 • p^2<span>=<span><span>p^10/</span><span>p^3</span></span></span><span>=<span>p7
</span></span>
Step-by-step explanation:
L.H.S
tanA * cosecA
=sinA/cosA * 1/sinA
now cancel sinA and sinA
then,
1/cosA
= secA
= RHS
hence proved
0, -4, -8, -12, -16, -20, -24, -28, -32, -36, -40, -44, -48, -52, -56, -60, -64, -68, -72, -76, -80, -84, -88, -92, -96, -100, -104, -108
-108 is the 28th term. This is one way to do it (to visualize it the long way).
Hope this helps :)
Answer:
x=-1
Step-by-step explanation:
Answer:
Assignment: 01.07 Laboratory TechniquesAssignment: 01.07 Laboratory Techniques
Step-by-step explanation:
Assignment: 01.07 LaboratoryAssignment: 01.07 Laboratory Techniques TechniquesAssignment: 01.07 Laboratory TechniquesAssignment: 01.07 Laboratory Techniques