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Nostrana [21]
3 years ago
8

Find the product for the following expressions: (8c + 2)(5c-7)

Mathematics
2 answers:
Marianna [84]3 years ago
8 0

Answer:40c^2-46c -14

Step-by-step explanation:

(8c+2)*(5c-7)

8c*(5c-7)+2(5c-7)

40c^2-56c+10c-14

40c^2-46c-14

klio [65]3 years ago
3 0

<u>Answer:</u>

<h2>(8c + 2)(5c-7) = 40c²-46c-14</h2>

<u>Explanation:</u>

(8c + 2)(5c-7) = 40c²-56c+10c-14

(8c + 2)(5c-7) = 40c²-46c-14

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The amount of money spent on textbooks per year for students is approximately normal.
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Answer:a

a

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b

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c

The  margin of error will decreases

d

The 99% confidence interval is  0.4107 <  p  < 0.4293

Step-by-step explanation:

From the question we are  told that

   The sample size  n =  19

    The sample mean is  \= x  = \$\  390

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Given that the confidence level is  95% then the level of significance is mathematically represented as

           \alpha = 100 -  95

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Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table

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The  margin of error is mathematically represented as

      E =  Z_{\frac{\alpha }{2} } *  \frac{\sigma}{\sqrt{n} }

=>    E = 1.96 *  \frac{120}{\sqrt{19} }

=>   E = 53.96

The 95% confidence interval is  

     \= x  -  E  <  \mu < \= x  +  E

=>   390  -   53.96   <  \mu < 390  -   53.96

=>  336.04    <  \mu < 443.96

When the confidence level increases the Z_{\frac{\alpha }{2} } also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

         n  \  \ \alpha  \ \  \frac{1}{E^2 }

So if the sample size increases the margin of error decrease

The  sample proportion is mathematically represented as

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<em><u /></em>

<em>                                                </em><em><u>Hope this helps :)</u></em>

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<em><u /></em>

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