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nalin [4]
2 years ago
11

Is -2×10 greater than 10?

Mathematics
1 answer:
Luba_88 [7]2 years ago
8 0
No, because it's -20 D:
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Factor Completely.<br> 12k^2-16k-60
faltersainse [42]

Answer:

4(k - 3)(3k + 5)

Step-by-step explanation:

Given

12k² - 16k - 60 ← factor out 4 from each term

= 4(3k² - 4k - 15) ← factor the quadratic

Consider the factors of the product of the coefficient of the k² term and the constant term which sum to give the coefficient of the k term

product = 3 × - 15 = - 45 , sum = - 4

Factors are - 9 and + 5

Use these factors to split the middle term

3k² - 9k + 5k - 15 → ( factor the first/second and third/fourth terms

= 3k(k - 3) + 5(k - 3) ← factor out (k - 3)

= (k - 3)(3k + 5)

Hence

12k² - 16k - 60 = 4(k - 3)(3k + 5) ← in factored form

8 0
3 years ago
Read 2 more answers
Write an equation in slope-intercept form for the line that passes through the point (-8, 2) and is perpendicular to the line y
tamaranim1 [39]

Answer:

y = -5x/4 - 8

Step-by-step explanation:

Two lines that are perpendicular have slopes that are opposite reciprocals.

Since the slope of the given line is 4/5, the opposite reciprocal of that is -5/4. So the equation has a slope of -5/4.

Since we know the coordinate of a point of the other equation, we can plug that into the point-slope form equation y - y1 = m(x - x1):

y - 2 = -5/4(x-(-8))

Simplify:

y - 2 = -5/4(x+8)

y - 2 = -5x/4 - 10

So the equation in slope-intercept form is:

y = -5x/4 - 8

3 0
3 years ago
Cobalt-60 is used in the treatment of cancer. A sample contains 8 grams of Co-60 where k = 0.1308
masha68 [24]
You need to post more information.
8 0
3 years ago
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PLEASE HELP! Screenshot attached
nadya68 [22]

Answer:

( x - 6 ) ( x - 3 ) (x + 4)

Step-by-step explanation:


6 0
3 years ago
What is a solution to 4x+6&lt;(with a line under it ) 18
JulsSmile [24]

Answer:

\textbf{$x \in (-\infty, 3] $}\\

Step-by-step explanation:

\textup{Given:}\\$ 4x + 6 $\textup{Subtracting $6$ from both the sides }\\$ 4x \leq 18 - 6 \hspace{5mm} (=12) $\\\textup{Dividing by $4$ on both the sides: \hspace{15mm} [Note that the sign of the inequality changes only when we divide it by a negative number]}\\$$ x \leq 3 $$\\\textup{$x$ can be any real number less than or equal to 3.}\\$ \iff x \in R^- \cup \{a : 0 \leq a \leq 3\} $

7 0
3 years ago
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