What number is 12% of 90

Pls help as soon as possible thank you

lina2011 [118]

Answer:

The domain corresponds to the values of the x and the range to the values of the y. So:

D: {-3, 0, 3}

R: {-6, 0, 6}

6 0

3 years ago

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I need help getting how do i do this??

Dovator [93]

Answer:

5 units

Step-by-step explanation:

By distance formula:

$r = \sqrt{(4 - 1) ^{2} + {(7 - 3)}^{2} } \\ \\ r = \sqrt{ {3}^{2} + {4}^{2} } \\ \\ r = \sqrt{9 + 16} \\ \\ r = \sqrt{25} \\ \\ r = 5$

8 0

2 years ago

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The magic dragon cigarette company claims that their cigarettes contain an average of only 10 mg of tar. a random sample of 100

9966 [12]

Answer:

$t=\frac{11.5-10}{\frac{4.5}{\sqrt{100}}}=3.333$

Critical value

The significance is 5% so then $\alpha=0.05$ and $\alpha/2=0.025$ then the critical value for this case would be $z_{\alpha/2}= 1.64$ . Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis and we can conclude that the true mean is higher than 10 mg

P value

The p value would be given

$p_v =P(z>3.333)=0.000434$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 10 mg

Step-by-step explanation:

Information given

$\bar X=11.5$ represent the sample mean

$\sigma=4.5$ represent the population standard deviation

$n=100$ sample size

$\mu_o =10$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is higher than 10mg, the system of hypothesis would be:

Null hypothesis: $\mu \leq 10$

Alternative hypothesis: $\mu > 10$

the statistic for this case would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing we got:

$t=\frac{11.5-10}{\frac{4.5}{\sqrt{100}}}=3.333$

Critical value

The significance is 5% so then $\alpha=0.05$ and $\alpha/2=0.025$ then the critical value for this case would be $z_{\alpha/2}= 1.64$ . Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis and we can conclude that the true mean is higher than 10 mg

P value

The p value would be given

$p_v =P(z>3.333)=0.000434$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 10 mg

6 0

3 years ago

Select the correct answer. Which type of association is shown in this scatter plot?

Airida [17]

→Answer:

A. strong positive

→Step-by-step explanation:

Well looking at the following scatterplot we can tell it is not negative only positive.

So we can cross out B. and C.

Looking at the dots and how close they are to creating a line we can decuct answer choice A. Because it is a strong positive.

4 0

3 years ago

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I only need help with number 2 it just doesn't make sense to me

hammer [34]

Just do simple cross method muliply both numerator ×7 and denominator ×7 and then see how many time 7 go into that number

7 0

3 years ago