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allochka39001 [22]
3 years ago
12

5/9 multiplied by 10/7

Mathematics
2 answers:
inessss [21]3 years ago
7 0
\frac{5}{9}\cdot\frac{10}{7} = \frac{50}{63}
Eduardwww [97]3 years ago
4 0
The answer to this problem is 7/18
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Find the area of the irregular figure. Round to the nearest hundredth.
RSB [31]

Answer:

67.5\text{ [square units]}

Step-by-step explanation:

The composite figure consists of one rectangle and two triangles. We can add up the area of these individual shapes to find the total area of the irregular figure.

<u>Formulas</u>:

  • Area of rectangle with base b and height h: A=bh
  • Area of triangle with base b and height h: A=\frac{1}{2}bh

By definition, the base and height must intersect at a 90 degree angle.

The rectangle has a base of 10 and a height of 5. Therefore, its area is A=10\cdot 5=50.

The smaller triangle to the left of the rectangle has a base of 2 and a height of 5. Therefore, its area is A=\frac{1}{2}\cdot 2\cdot 5=5.

Finally, the larger triangle on top of the rectangle has a base of 5 and a height of 5. Therefore, its area is A=\frac{1}{2}\cdot 5\cdot 5=12.5.

Thus, the area of the total irregular figure is:

50+5+12.5=\boxed{67.5\text{ [square units]}}

7 0
3 years ago
Please help me with this
Sonja [21]
The answer to your question is D) √5x/5x.

I hoped this helped!
6 0
3 years ago
⚠️URGENT PLS HELPPPPP<br><br> LINKS WILL BE REPORTED
balu736 [363]
The answer is the last one
6 0
3 years ago
a father is now 38 years older than his son. Ten years ago he was twice as old as his son. let x represent the age of the son no
Helga [31]

The present age of father is 86 years old and present age of son is 48 years old

<em><u>Solution:</u></em>

Given that, a father is now 38 years older than his son

Ten years ago he was twice as old as his son

Let "x" be the age of son now

Therefore, from given,

Father age now = 38 + age of son now

Father age now = 38 + x

<em><u>Ten years ago he was twice as old as his son</u></em>

Age of son ten years ago = age of son now - 10

Age of son ten years ago = x - 10

Age of father ten years ago = 38 + x - 10

Then we get,

Age of father ten years ago = twice the age of son ten years ago

38 + x - 10 = 2(x - 10)

28 + x = 2x - 20

2x - x = 28 + 20

x = 48

Thus son age now is 48 years old

Father age now = x + 38 = 48 + 38 = 86

Thus present age of father is 86 years old and present age of son is 48 years old

7 0
3 years ago
Answer quick pleaseeeeeee
masha68 [24]

Answer:

I believe its Orange

Step-by-step explanation:

2/3 is greater than all other ratios

5 0
3 years ago
Read 2 more answers
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