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lbvjy [14]
2 years ago
11

1/4x -5=3/4x-12 show two different ways to solve

Mathematics
1 answer:
aniked [119]2 years ago
3 0

Answer:

In the two different ways we have solved the given equation as

Step-by-step explanation:

Given expression is

To simplify the given expression in two ways:

First way:

Given  

Multiplying 3 on both sides

 (adding the like terms)

Dividing by 3 on both sides

Therefore the given expression is solved that

Another way:

Given  

(adding the like terms)

Therefore the given expression is solved that

In the two different ways we have solved the given equation as

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If j // l, m<1 = 135, m<2 = 55, and m<3 = 45, list all other parallel lines. Justify your answers. Show work if any.
sergejj [24]

Answer:

Step-by-step explanation:

The supplement to ∠1 = 180°-135° = 45° = ∠3, so m is parallel to j and l.

∠2 ≠ 45° and ∠2 ≠ 135°, so k is not parallel to j, l, or m.

3 0
2 years ago
Find the slope of the line containing the pair points (9,5) (6,4)
joja [24]

Answer:

y=1/3x+2

Step-by-step explanation:

3 0
3 years ago
Choose the correct graph of the following condition.<br> {(x, y) : x = 4) o [(x,y): y = 4)
Studentka2010 [4]

Answer:

There is no solution

Step-by-step explanation:

7 0
3 years ago
Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software,
vichka [17]

Answer:

A(-1,0) is a local maximum point.

B(-1,0)  is a saddle point

C(3,0)  is a saddle point

D(3,2) is a local minimum point.

Step-by-step explanation:

The given function is  

f(x,y)=x^3+y^3-3x^2-3y^2-9x

The first partial derivative with respect to x is  

f_x=3x^2-6x-9

The first partial derivative with respect to y is  

f_y=3y^2-6y

We now set each equation to zero to obtain the system of equations;

3x^2-6x-9=0

3y^2-6y=0

Solving the two equations simultaneously, gives;

x=-1,x=3  and y=0,y=2

The critical points are

A(-1,0), B(-1,2),C(3,0),and D(3,2).

Now, we need to calculate the discriminant,

D=f_{xx}(x,y)f_{yy}(x,y)-(f_{xy}(x,y))^2

But, we would have to calculate the second partial derivatives first.

f_{xx}=6x-6

f_{yy}=6y-6

f_{xy}=0

\Rightarrow D=(6x-6)(6y-6)-0^2

\Rightarrow D=(6x-6)(6y-6)

At A(-1,0),

D=(6(-1)-6)(6(0)-6)=72\:>\:0 and f_{xx}=6(-1)-6=-18\:

Hence A(-1,0) is a local maximum point.

See graph

At B(-1,2);

D=(6(-1)-6)(6(2)-6)=-72\:

Hence, B(-1,0) is neither a local maximum or a local minimum point.

This is a saddle point.

At C(3,0)

D=(6(3)-6)(6(0)-6)=-72\:

Hence, C(3,0) is neither a local minimum or maximum point. It is a saddle point.

At D(3,2),

D=(6(3)-6)(6(2)-6)=72\:>\:0 and f_{xx}=6(3)-6=12\:>\:0

Hence D(3,2) is a local minimum point.

See graph in attachment.

3 0
3 years ago
X/7=21 what is the answer
Tems11 [23]
<span>here is the answer x = -147

Hope its the answer

</span>
5 0
3 years ago
Read 2 more answers
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