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tangare [24]
3 years ago
12

Describe the operation used to solve the equation 5/6 x - 2= -2/3 x + 1

Mathematics
1 answer:
yuradex [85]3 years ago
3 0

Answer:

I love algebra anyways  

the ans is in the picture with the steps  

(hope it helps can i plz have brainlist :D hehe)

Step-by-step explanation:

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Y would equal 5x+24 because u can only combined the compounds together
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the volume of a cylinder = V=Ah =pirsqh

=pie × r sq × h

= 3.14×4 ×4×9 = 452.16 so thats eliminated?

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= 1/3×3.14×4×4×9 = 150.72

volume of cylinder = 2×pi×r×h+2×pi× r×r

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Need help Giving 13 points
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Read Exp:

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1.) 4 is the Base and 8 is the Exponent.

2.) 9^4 = 9 x 9 x 9 x 9 = 6561.

3.) (-5)^2 = -5 x -5 = 25.

4.) 3^3 = 3 x 3 x 3 = 27.

5.) (1/2)^5 = 1/2 x 1/2 x 1/2 x 1/2 x 1/2 = 0.03125

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* 1/32

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Complete the square to re-write the quadratic function vertex form:
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Functionally important traits in animals tend to vary little from one individual to the next within populations, possibly becaus
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Answer:

Step-by-step explanation:

Hello!

Given the variable

X:  Ratio of the length to width of the anterior semicircular canals (SC) of the three-toed sloth.

The researcher's claim is that the ratio of the SC of the sloths is more variable than in other animal species that are more active.

For more active species the standard deviation of the ratio is σ= 0.09

1)

To calculate the sample standard deviation you have to calculate the sample variance first:

S^2= \frac{1}{n-1} [sumX^2-\frac{(sumX)^2}{n} ]

n=7; ∑X= 8.91; ∑X²= 11.8599

S^2= \frac{1}{6} [11.5899-\frac{(8.91)^2}{7} ]= 0.0287= 0.029

S= √S²= √0.029= 0.169≅ 0.17

The sample standard deviation of the ratio is 0.17

2)

The parameter of interest is the population standard deviation. To calculate a confidence interval for the standard deviation of a population you have to estimate the population variance first. Then calculate the square root of both limits of the interval for the variance to obtain the interval for the standard deviation.

The statistic to use is the Chi-Square and the formula for the interval is:

[\frac{(n-1)S^2}{X^2_{n-1;1-\alpha /2}} ;\frac{(n-1)S^2}{X^2_{n-1;\alpha /2}} ]

X^2_{n-1;\alpha /2}= X^2_{6; 0.025}= 1.2373

X^2_{n-1;1-\alpha /2}= X^2_{6; 0.975}= 14.449

[\frac{6*0.029}{14.449} ;\frac{6*0.029}{1.2373} ]\\

[0.0120; 0.1406]

Using a 95% confidence level you'd expect the interval [0.0120; 0.1406] to include the true value of the population variance of the ratio of the length to width of the anterior semicircular canals (SC) of the three-toed sloths.

Now you have to calculate the square root of each limit:

[√0.0120; √0.1406]

[0.1097; 0.3750]

Using a 95% confidence level you'd expect the interval [0.1097; 0.3750] to include the true value of the population standard deviation of the ratio of the length to width of the anterior semicircular canals (SC) of the three-toed sloths.

3)

As you can see the calculated interval doesn't include the value obtained for the other species.

I hope this helps!

5 0
3 years ago
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