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Solnce55 [7]
4 years ago
12

Lyril inspects sneakers at a

Mathematics
1 answer:
NISA [10]4 years ago
4 0

Answer:

0.8

Step-by-step explanation:

Of the 60 sneakers inspected, 48 were acceptable.  The experimental probability is therefore:

P = 48/60

P = 0.8

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AysviL [449]

2)The circumference or perimeter of a circle with radius r is

P=2\pi r. Given P=28\pi. Therefore,

2\pi r =28\pi \\ r=14\\ d=2r=28\\ A=\pi r^2 \\ A=\pi (14)^2\\ A=[tex] 196\pi

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7 0
3 years ago
What are the zeros of the function
aleksklad [387]

Answer:

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Description

DescriptionIn mathematics, a zero of a real-, complex-, or generally vector-valued function, is a member of the domain of such that vanishes at; that is, the function attains the value of 0 at, or equivalently, is the solution to the equation. A "zero" of a function is thus an input value that produces an output of

4 0
3 years ago
The sum of two numbers is 95. If the larger is increased by twice the smaller, the result is 120. Find the numbers.
adelina 88 [10]
Hello!

You can make two expressions based on what you know

let x equal the larger number
let y equal the smaller number

x + y = 95
x + 2y = 120

We can use elimination to get rid of x

You can subtract the two equation to get rid of x

-y = -25

Since y is negative we can multiply both sides by -1 to make y positive

y = 25

Now we can put this into one of the other equations to find x

x + 25 = 95

subtract 95 from both sides

x = 70

The answers are 70 and 25

Hope this helps!
3 0
3 years ago
Please help I am so lost!!!
ASHA 777 [7]
\bf tan\left( \frac{x}{2} \right)+\cfrac{1}{tan\left( \frac{x}{2} \right)}\\\\
-----------------------------\\\\
tan\left(\cfrac{{{ \theta}}}{2}\right)=
\begin{cases}
\pm \sqrt{\cfrac{1-cos({{ \theta}})}{1+cos({{ \theta}})}}
\\ \quad \\

\cfrac{sin({{ \theta}})}{1+cos({{ \theta}})}
\\ \quad \\

\boxed{\cfrac{1-cos({{ \theta}})}{sin({{ \theta}})}}
\end{cases}\\\\

\bf -----------------------------\\\\
\cfrac{1-cos(x)}{sin(x)}+\cfrac{1}{\frac{1-cos(x)}{sin(x)}}\implies \cfrac{1-cos(x)}{sin(x)}+\cfrac{sin(x)}{1-cos(x)}
\\\\\\
\cfrac{[1-cos(x)]^2+sin^2(x)}{sin(x)[1-cos(x)]}\implies 
\cfrac{1-2cos(x)+\boxed{cos^2(x)+sin^2(x)}}{sin(x)[1-cos(x)]}
\\\\\\
\cfrac{1-2cos(x)+\boxed{1}}{sin(x)[1-cos(x)]}\implies \cfrac{2-2cos(x)}{sin(x)[1-cos(x)]}
\\\\\\
\cfrac{2[1-cos(x)]}{sin(x)[1-cos(x)]}\implies \cfrac{2}{sin(x)}\implies 2\cdot \cfrac{1}{sin(x)}\implies 2csc(x)
4 0
3 years ago
Which of the following equations are correct !! Choose 2 answers please !! I WILL MARK BRAINLIST
maks197457 [2]

Answer:

B and C are correct

Step-by-step explanation:

17/4 = 4.25

4 and 1/4 = 17/4

3 0
3 years ago
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