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3 years ago

Do they put on laughing gas for when you get your braces? And do they numb your teeth-?

Mathematics

1 answer:

tekilochka [14]3 years ago

4 0

Answer:

no to both questions, they might numb your gums but im not 100% sure.

Step-by-step explanation:

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An amphitheater charges $75 for each seat in Section A, $55 for each seat in Section B, and $30 for each lawn seat. There are th

Ratling [72]

<span>Section A seats = 1500 Section B seats = 4500 Lawn seats = 17000 Let's write a few equations to express what we know. A = number of seats in section A B = number of seats in section B L = number of law seats "There are three times as many seats in Section B as in Section A" B = 3A "all 23,000 seats" L = 23000 - A - B L = 23000 - A - 3A "The revenue from selling all 23,000 seats is $870,000" 870000 = 30L + 55B + 75A Now let's substitute 3A for B 870000 = 30L + 55(3A) + 75A And substitute (23000 - A - 3A) = (23000 - 4A) for L 870000 = 30(23000 - 4A) + 55(3A) + 75A And solve for A 870000 = 30(23000 - 4A) + 55(3A) + 75A 870000 = 690000 - 120A + 165A + 75A 870000 = 690000 + 120A 180000 = 120A 1500 = A So we know that section A has 1500 seats. Because of B = 3A = 3*1500 = 4500, section B has 4500 seats. Finally, L = 23000 - A - B = 23000 - 1500 - 4500 = 17000 seats</span>

3 0

3 years ago

Find the mean of the data summarized in the given frequency distribution . Compare the computed mean to the actual mean of 57.6

AlexFokin [52]

The mean of the frequency distribution is 52.6° F. The computed mean of 52.6° F is lesser than the actual mean of 57.6° F.

<h3>What is the mean of a distribution?</h3>

The mean of the distribution can be defined as the average value of the distribution, It can be expressed as the total sum of all the observed values divided by the frequency of the distribution.

From the parameters given:

Low-temperature Frequency

40 - 44 2

45 - 49 5

50 - 54 9

55 - 59 6

60 - 64 3

The first thing to do is to determine the class midpoint. The class midpoint is the sum of the class interval divided by 2.

The class midpoint of 40 - 44 is $\mathbf{\dfrac{40 + 44}{2} = 42}$

The class midpoint of 45 - 49 is $\mathbf{\dfrac{45 + 49}{2} = 47}$

The class midpoint of 50 - 54 is $\mathbf{\dfrac{50 + 54}{2} = 52}$

The class midpoint of 55 - 59 is $\mathbf{\dfrac{55 + 59}{2} = 57}$

The class midpoint of 60 - 64 is $\mathbf{\dfrac{60 + 64}{2} = 62}$

Now, the table can be represented as:

Low-temperature Frequency x

40 - 44 2 42

45 - 49 5 47

50 - 54 9 52

55 - 59 6 57

60 - 64 3 62

The mean can now be determined as follows:

$\mathbf{\bar x = \dfrac{\sum fx}{\sum f }}$

$\mathbf{\bar x = \dfrac{(2 \times 42)+ (5 \times 47) + ( 9\times 52) +(6\times 57) + (3 \times 62)}{2 + 5 + 9 + 6 + 3 }}$

$\mathbf{\bar x = \dfrac{1315}{25}}$

$\mathbf{\bar x = 52.6}$

Therefore, we can conclude that the mean of the frequency distribution is 52.6° F. The computed mean of 52.6° F. is lesser than the actual mean of 57.6° F

Learn more about the mean of frequency distribution here:

brainly.com/question/12269435

3 0

2 years ago

Explain the following composite numbers into product of prime factors.<br>5929

Alexxx [7]

Since, the prime factors of 5929 are 7, 11. Therefore, the product of prime factors = 7 × 11 = 77.

7 0

2 years ago

Roxanne bought a 40-inch television that measures 24 inches in height. What is the width of the television?

Natali5045456 [20]

Answer: