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3 years ago

3/8 x 2/3 pls I really need this

2 answers:

4 0

$\bf \cfrac{\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}{\underset{4}{\begin{matrix} 8 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}}\times \cfrac{\stackrel{1}{\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}}{\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}\implies \cfrac{1}{4}$

Andrew [12]3 years ago

4 0

3 x 2

8 x 3

1/4

You just multiply both numerator then multiply both the bottom numbers

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2 years ago

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2 years ago

find the area of the window 24inch by 30inch and convert in to square feet, round the anwser to the second decimal place

Nezavi [6.7K]

Answer:

5 sq. ft.

Step-by-step explanation:

To find the area of a rectangle, use this formula: A = lw.

Because you know two side lengths of the window, you can just plug in the numbers to the formula.

But not yet! You need to convert the given lengths into feet first.

You know that there are 12 inches in 1 foot.

So:

24 inches ÷ 12 inches/foot = 2 feet

30 inches ÷ 12 inches/foot = 2.5 feet

Alright, now you can plug in these lengths into the formula.

A = (2) (2.5) = 5 sq. ft.

The question asks you to round, but there is nothing to round, so you are done here.

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3 years ago

Solve the differential. This was in the 2016 VCE Specialist Maths Paper 1 and i'm a bit stuck

Nimfa-mama [501]

$\sqrt{2 - x^{2}} \cdot \frac{dy}{dx} = \frac{1}{2 - y}$
$\frac{dy}{dx} = \frac{1}{(2 - y)\sqrt{2 - x^{2}}}$

Now, isolate the variables, so you can integrate.
$(2 - y)dy = \frac{dx}{\sqrt{2 - x^{2}}}$
$\int (2 - y)\,dy = \int\frac{dx}{\sqrt{2 - x^{2}}}$
$2y - \frac{y^{2}}{2} = sin^{-1}\frac{x}{\sqrt{2}} + \frac{1}{2}C$

$4y - y^{2} = 2sin^{-1}\frac{x}{\sqrt{2}} + C$
$y^{2} - 4y = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} - 4 = -2sin^{-1}\frac{x}{\sqrt{2}} - C$
$(y - 2)^{2} = 4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C$

$y - 2 = \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$
$y = 2 \pm\sqrt{4 - 2sin^{-1}\frac{x}{\sqrt{2}} - C}$

At x = 1, y = 0.
$0 = 2 \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$
$-2 = \pm\sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C > 0$
$\therefore 2 = \sqrt{4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C}$

$4 = 4 - 2sin^{-1}\frac{1}{\sqrt{2}} - C$
$0 = -2sin^{-1}\frac{1}{\sqrt{2}} - C$
$C = -2sin^{-1}\frac{1}{\sqrt{2}} = -2\frac{\pi}{4}$
$C = -\frac{\pi}{2}$

$\therefore y = 2 - \sqrt{4 + \frac{\pi}{2} - 2sin^{-1}\frac{x}{\sqrt{2}}}$

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3 years ago

Who can solve this question!!?!?

Tpy6a [65]

Answer: i cant see the picture can you send it to me please

Step-by-step explanation:

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3 years ago