Answer:
#1
x intercept is -5
y intercept is -5
#2
y=8x
Step-by-step explanation:
Answer:
You did not post the options, but i will try to answer this in a general way.
Because we have two solutions, i know that we are talking about quadratic equations, of the form of:
0 = a*x^2 + b*x + c.
There are two easy ways to see if the solutions of this equation are real or not.
1) look at the graph, if the graph touches the x-axis, then we have real solutions (if the graph does not touch the x-axis, we have complex solutions).
2) look at the determinant.
The determinant of a quadratic equation is:
D = b^2 - 4*a*c.
if D > 0, we have two real solutions.
if D = 0, we have one real solution (or two real solutions that are equal)
if D < 0, we have two complex solutions.
Answer:
72m^3
Step-by-step explanation:
l x w x h
l = 2
w = 9
h = 4
2 x 9 x 4 = 72
Answer:
The total workers are<u> 2400.</u>
Step-by-step explanation:
Given:
In company 80% of the workers are women.
480 workers are men.
Now, to find the total workers in all.
<u><em>In first way:</em></u>
If women are 80%, then men would be 100-80 = 20%.
Let the total workers be
.
According to question:

⇒
⇒
⇒
Dividing both sides by 0.20 we get:
⇒
.
Total workers = 2400.
<em><u>Now, in second way</u></em>.
Again, let the total workers be
.
According to question:

⇒
<em>On solving:</em>
⇒
⇒
<em>Dividing both sides by 0.20 we get:</em>
⇒
.
<em>Total workers = 2400.</em>
Therefore, the total workers are <u>2400</u>.
Answer:
The degrees of freedom are given by:

The significance level is
and then the critical value can be founded in th chi square table we need a quantile that accumulates 0.05 of the area in the right tail of the distribution and for this case is:

And if the chi square statistic is higher than the critical value we can reject the null hypothesis in favor of the alternative.
Step-by-step explanation:
We have the followign system of hypothesis:
Null hypothesis: 
Alternative hypothesis: 
The degrees of freedom are given by:

The significance level is
and then the critical value can be founded in th chi square table we need a quantile that accumulates 0.05 of the area in the right tail of the distribution and for this case is:

And if the chi square statistic is higher than the critical value we can reject the null hypothesis in favor of the alternative.