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4 years ago

Which describes fat?

1 answer:

Nutka1998 [239]4 years ago

6 0

The correct answer is (C), this is because (A) talks about producing energy as of where fat is a form of storing energy. (B) is talking about a cell that controls its surroundings which, as we know, is not the job of fat. That leaves (D) to rule out as it is a textbook definition of an enzyme.

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Which element would be dull and brittle?<br> A. Niobium (Nb)<br> B. Lithium (LI)<br> C. Bromine (Br)

Mars2501 [29]

Answer:

I am pretty sure it's Lithium because it's a light and soft metal. Bromine is a liquid so that cant be it and Niobium is a light gray crystalline (crystal/ sharp not dull).

Hope this helps :)

Explanation:

4 0

3 years ago

The a-helices and b- sheets in protein make up its

Marta_Voda [28]

Alpha helix and beta sheets are the secondary structure of protein

5 0

3 years ago

Consider the reaction below.

nikitadnepr [17]

The net ionic equation of the reaction could be determined by cancelling out the like ions between both sides of the reaction. These ions are called spectator ions. They are called as such because they do not actively participate in the reaction. The spectator ions are Na+ and Cl-. When you cancel those, the equation would become letter D.

6 0

4 years ago

Read 2 more answers

When 70.4 g of benzamide (C7H7NO) are dissolved in 850. g of a certain mystery liquid X , the freezing point of the solution is

lora16 [44]

Answer:

i=1.62 .

Explanation:

Let, i be the Van't Hoff Factor.

Moles of benzamide,= $\dfrac{Mass}{molar\ mass}=\dfrac{70.4}{121.14}=0.58\ mol.$

Molality of solution, m= $\dfrac{moles }{mass\ of\ solvent}=\dfrac{0.58}{0.85}=0.68\ molal.$

Now, we know

Depression in freezing point, $\Delta T=i\times K_f\times m$ .....1

It is given that,

$\Delta T=2.7^o C\\i=1 ( since\ it\ is\ non\ dissociable\ solutes)\\K_f ( freezing\ constant)\\$

Putting all these values we get,

$K_f=3.949\ C/m.$

Now, moles of ammonium chloride= $\dfrac{70.4}{53.49}=1.316\ mol.$

molality = $\dfrac{1.316}{0.85}=1.54 molal.\\\Delta T=9.9 .$

Putting all these values in eqn 1.

We get,

i=1.62 .

Hence, this is the required solution.

6 0

3 years ago

Identify the charge carried by a phosphide ion

insens350 [35]

Answer : The charge carried by a phosphide ion is, (-3)

Explanation :

In phosphide ion, the (-ide) indicates that the phosphide ion is the anion of phosphorous. So, we will have to add electrons.

As we know that the phosphorous belongs to group 5 and have 5 valence electrons.

The atomic number of phosphorous = 15

The electronic configuration of phosphorous is, $1s^22s^22p^63s^23p^3$

In phosphorous, the 'p' sub-shell is half filled. For fully filled 'p' sub-shell, we will need '3' electrons. By adding 3 electrons in 'p' sub-shell of phosphorous, (-3) charge will be created on phosphorous and named as phosphide ion.

Phosphide ion is written as, $P^{3-}$

5 0

3 years ago