The a-helices and b- sheets in protein make up its
1 answer:
You might be interested in
Answer:
0.33 mol/kg NH₃
Explanation:
Data:
b(NH₃) = 0.33 mol/kg
b(Na₂SO₄) = 0.10 mol/ kg
Calculations:
The formula for the boiling point elevation ΔTb is
i is the van’t Hoff factor — the number of moles of particles you get from a solute.
(a) For NH₃,
The ammonia is a weak electrolyte, so it exists almost entirely as molecules in solution.
1 mol NH₃ ⟶ 1 mol particles
i ≈ 1, and ib = 1 × 0.33 = 0.33 mol particles per kilogram of water
(b) For Na₂SO₄,
Na₂SO₄(aq) ⟶ 2Na⁺(aq) + 2SO₄²⁻(aq)
1 mol Na₂SO₄ ⟶ 3 mol particles
i = 1 and ib = 3 × 0.10 = 0.30 mol particles per kilogram of water
The NH₃ has more moles of particles, so it has the higher boiling point.
Answer : The correct option is, (C) 1.7
Explanation :
First we have to calculate the moles of and
.
The balanced chemical reaction will be:
0.01 mole of dissociate to give 0.01 mole of
ion and 0.02 mole of
ion
and
0.03 mole of dissociate to give 0.03 mole of
ion and 0.03 mole of
ion
That means,
0.02 moles of ion neutralize by 0.02 moles of
ion.
The excess moles of ion = 0.03 - 0.02 = 0.01 mole
Total volume of solution = 100 + 300 = 400 ml = 0.4 L
Now we have to calculate the concentration of ion.
Now we have to calculate the pH of the solution.
Therefore, the pH of the solution is, 1.7