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sergey [27]
3 years ago
15

The a-helices and b- sheets in protein make up its

Chemistry
1 answer:
Marta_Voda [28]3 years ago
5 0
Alpha helix and beta sheets are the secondary structure of protein
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Physical Science pre-Test 2020-2021
poizon [28]

Answer:

exothermic I think

Explanation:

IM TWKIGN THE TEST

4 0
2 years ago
Match the following items.
navik [9.2K]

Answer:

1. not affected by a magnet                      1 liquid

2. mostly space                                          2 solid

3. flows freely but particles still attract 3 proton

4. positively charged particles                  4 gas

5. free to move in all space                       5 alpha particles

6. negatively charged particles                 6 atoms

7. atoms nearly fixed in space                   7 gamma ray                                                    8. helium nucleus                                        8 electron (beta)

6 0
2 years ago
How many electrons are present in outermost shell of argon atom​
sattari [20]

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7 0
2 years ago
Read 2 more answers
What is the empirical formula for a compound that contains 10.89% magnesium 31.77% chloride and 57.34% oxygen
Blizzard [7]

Answer: Mg_{1}Cl_{2}O_{8}

Explanation:

If percentage are given then we are taking total mass is 100 grams.So, the mass of each element is equal to the percentage given.

Mass of Mg = 10.89 g

Mass of Cl = 31.77 g

Mass of O = 57.34 g

Step 1 : convert given masses into moles.

Moles of Mg=\frac {\text{ given mass of Mg}}{\text{ molar mass of Mg}}= \frac {10.89g}{24g/mole}=0.45moles

Moles of Cl = \frac {\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac {31.77g}{35.5g/mole}=0.89moles

Moles of O =\frac {\text{ given mass of O}}{\text{ molar mass of O}}=\frac {57.34g}{16g/mole}=3.58moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Mg = \frac {0.45}{0.45}=1

For Cl = \frac {0.89}{0.45}=2

For O= \frac {3.58}{0.45}=8

The ratio of Mg :Cl : O= 1 : 2 : 8

Hence the empirical formula is Mg_{1}Cl_{2}O_{8}

4 0
2 years ago
Please someone help me Balance this equation.
NeTakaya

Answer: This is an oxidation-reduction (redox) reaction:

3 C-II - 12 e- → 3 CII (oxidation)

4 CrVI + 12 e- → 4 CrIII (reduction)

C2H5OH is a reducing agent, K2Cr2O7 is an oxidizing agent.

7 0
2 years ago
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