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<span> x ( x+4) = 45 </span>
<span>5m X 5m AND 8m X 8m
</span>
5) x ( x+6) = 135
<span>x^2 +6x -135 = 0 </span>
<span>( x-9) ( x+15) = 0 </span>
<span>x = 9 </span>
<span>ANSWER 9 & 15</span>
Answer:
3?
Step-by-step explanation:
im not 100% sure
Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
Are you looking for slope?
if u r the slope is -6/3
The answer is A. -2+5i.
First you set up the problem like this: (6+2i)-(8-3i)
Then you distribute the (-) into the second parenthesis. After doing that you should have something that looks like this: 6+2i-8+3i
Then you add like terms.