Example 1:
The pros of Orthographic is that they can show hidden details and all of the connecting parts, they can be annotated to display material and finishes. The pros of Isometric projection is that they dont need many views and it gives accuracy, cons are is created a unorginized apperance by the lack of foreshortening, I would choose Isometric projection because it shows the size of the figure.
Example 2:
Orthographic projection is a good option for showing lots of detail and small things. The limitation is that with all of that detail, they can become quite messy and hard to understand to someone new to them. However, that is one of the pros of Isometric projection. It gives easy detail and is just as good as an Orthographic. Personally, I find Isometric projections easier to interpret.
Answer: 0 y=x+10
Step-by-step explanation:
Answer:
=========
<h2>Given</h2>
<h3>Line 1</h3>
<h3>Line 2</h3>
- Passing through the points (4, 3) and (5, - 3)
<h2>To find</h2>
- The value of k, if the lines are perpendicular
<h2>Solution</h2>
We know the perpendicular lines have opposite reciprocal slopes, that is the product of their slopes is - 1.
Find the slope of line 1 by converting the equation into slope-intercept from standard form:
<u><em>Info:</em></u>
- <em>standard form is ⇒ ax + by + c = 0, </em>
- <em>slope - intercept form is ⇒ y = mx + b, where m is the slope</em>
- 3x - ky + 7 = 0
- ky = 3x + 7
- y = (3/k)x + 7/k
Its slope is 3/k.
Find the slope of line 2, using the slope formula:
- m = (y₂ - y₁)/(x₂ - x₁) = (-3 - 3)/(5 - 4) = - 6/1 = - 6
We have both the slopes now. Find their product:
- (3/k)*(- 6) = - 1
- - 18/k = - 1
- k = 18
So when k is 18, the lines are perpendicular.
