$\dfrac{x}{-9}\geq3\qquad\text{change the signs}\\\\\dfrac{x}{9}\leq-3\qquad\text{multiply both sides by 9}\\\\9\!\!\!\!\diagup^1\cdot\dfrac{x}{9\!\!\!\!\diagup_1}\leq(-3)(9)\\\\x\leq-27$

5 0

3 years ago

2x^2-3x-9 please help

Romashka-Z-Leto [24]

Im assuming you mean 2x^2-3x-9=0 ?
If so, you have to factorise the equation
(2x-3) (x+3) = 0

2x - 3 = 0
2x = 3
x = 1.5

x + 3 = 0
x = -3

x is either 1.5 or -3

8 0

3 years ago

Read 2 more answers

Which is the solution of set?

Anna [14]

Answer:

the answer is x >0 hope this helped

4 0

3 years ago

Graph a line with a slope of.....

photoshop1234 [79]

Answer: