This is the concept of geometry, given that AB=AC, it means that the tirangle is isosceles, thus to get the value of AB and AC we proceed as follows;
thus using the cosine rule:
c^2=a^2+b^2-2abcosC
suppose\AB=AC=x
thus;
8^2=x^2+x^2-2*x*xcos15
64=2x^2-2x^2cos15
64=2x^2-1.9x^2
64=0.1x^2
x^2=640
x=sqrt640
x=25.3
hence;
AC=AB=25.3
Answer:
2x+11
Explanation: it’s the answer:)
It will take them 16 days to complete the job
<span>Alright, here's your answer.
y-intercept is computed (not found) by assigning x = 0 and computing y: here that is f(0) = Log(2*0 + 1) – 1 = Log(1) – 1 = 0 – 1 = -1
y-intercept is (0, -1)
x-intercept is computed by solving f(x) = 0 for x: here that is
0 = Log(2x + 1) – 1 → 1 = Log(2x + 1)
Assuming the Log cited is base 10, then 10^1 = 10^Log(2x + 1) = 2x + 1
That’s 10 = 2x + 1
Therefore 9 = 2x
x = 9/2 = 4.5
Check this result in the original equation, I did!
Your answer is - x-intercept is (4.5, 0)
I hope I helped! :)
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