Answer:
Error in the sphere's surface: 29 
and relative error in surface measure: 0.011
Error in the sphere's volume: 205 
and relative error in the volume measure: 0.017
Step-by-step explanation:
(a)
The measured length (l) of the circumference is 90 cm with an error of 0.5 cm, that is:
and with regards to the error:
then when we use the formula for the sphere's surface, we get:
Then the relative error in the surface is:
(b)
Use the formula for the volume of the sphere:
Then the relative error in the volume is:
It doesn’t really matter which variable you isolate first but usually you would use the one that’s by itself already. like for example one of the equations was y = 8. you would already have your y solve for so you would just have to plug that in for y in the other equation. personally, i usually do x first unless one of the equations has either x or y by itself already. i think its easier to just do x first and then solve for y after that, but it just depends on what the equations are; sometimes it might be easier to just do y first. hope this helps!
The area of a trapezoid is half its height multiplied by the sum of the lengths of its two bases.
6,550=1/2b(115+85)
<span>115+85= 200
1/2*200= 100
6,550/100=65.5
h=</span><span>65.5
</span>
The height is 65.5 cm
If you increased 5 to 10, then I would have doubled the number 5 and this is a 100% increases.
If you increased 5 to 7.5, then this is 50% increase, because 50% of 5 is 2.5 and 5 + 2.5 = 7.5
If you increased 5 to 6, then this is a 20% increase,because 5 + 1 = 6 and 1 is 20% of 5
If you increased 5 to 7, then this is a 40% increase,because 5 increased by 2, 5 + 2 = 7, and 2/5 = 40%
If you increased 5 to x, then 5 was increased by x/5×100%
For example 5 to 9 is a4/5×100%=80% increase
So here 5 increases by 8, 5 + 3 = 8, thus the percentage increase is3/5×100%=0.006
