Answer:
Arc length ![=\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx](https://tex.z-dn.net/?f=%3D%5Cint_0%5E%7B%5Cpi%7D%20%5Csqrt%7B1%2B%5B%284.5sin%284.5x%29%29%5D%5E2%7D%5C%20dx)
Arc length 
Step-by-step explanation:
The arc length of the curve is given by ![\int_a^b \sqrt{1+[f'(x)]^2}\ dx](https://tex.z-dn.net/?f=%5Cint_a%5Eb%20%5Csqrt%7B1%2B%5Bf%27%28x%29%5D%5E2%7D%5C%20dx)
Here,
interval ![[0, \pi]](https://tex.z-dn.net/?f=%5B0%2C%20%5Cpi%5D)
Now, 
![f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left ( [-cos(t)]_0^{4.5x} \right )](https://tex.z-dn.net/?f=f%27%28x%29%3D%5Cfrac%7B%5Cmathrm%7Bd%7D%20%7D%7B%5Cmathrm%7Bd%7D%20x%7D%5Cleft%20%28%20%5B-cos%28t%29%5D_0%5E%7B4.5x%7D%20%5Cright%20%29)


Now, the arc length is ![\int_0^{\pi} \sqrt{1+[f'(x)]^2}\ dx](https://tex.z-dn.net/?f=%5Cint_0%5E%7B%5Cpi%7D%20%5Csqrt%7B1%2B%5Bf%27%28x%29%5D%5E2%7D%5C%20dx)
![\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx](https://tex.z-dn.net/?f=%5Cint_0%5E%7B%5Cpi%7D%20%5Csqrt%7B1%2B%5B%284.5sin%284.5x%29%29%5D%5E2%7D%5C%20dx)
After solving, Arc length 
Just substitute it into the gradient formula which is: y2 - y1 / x2 - x1. So 2-3/2-9 = -1/-7 = 1/7
The answer is 12.64. I hope I helped. :)
Total = Principal * (1 + (rate/n))^n*years
where n is the number of compounding periods per year
Total = 12,500 * (1 + (.0275/4) )^40
Total = 12,500 * <span>(1.006875) ^40
</span>Total =
<span>
<span>
<span>
12,500 * 1.3152923995
</span>
</span>
</span>
Total =
16,441.16
Source:
http://www.1728.org/compint.htm
Answer:
4 solutions counting any possible multiplicity
Step-by-step explanation:
Recall that if one considers the Complex Number System, a polynomial has as many solutions (including multiplicity) as its degree.
So in this case, where we are considering a polynomial of order 4 Notice that the term
, is in reality the leading term (term with the highest power of the variable) of this polynomial.
Therefore, in the Complex Number System, this polynomial would have 4 solutions.