Answer:
1. 1760
2. 1400
Step-by-step explanation:
2^5 = 32
32 × 5 = 160
160 × 11 = 1760
2^3 = 8
5^2 = 25
8 × 25 = 200
200 × 7 = 1400
Answer:
a) 0.076
b) 0.5
c) 0.084
d) 0.25
e) 0.00024
f) 0.156
Step-by-step explanation:
a) In an ordinary deck there are 4 aces. The probability of getting an ace is given by:
![P=\frac{n}{N}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7Bn%7D%7BN%7D)
n: options for an ace = 4
N: total number of cards = 52
![P=\frac{4}{52}=0.076](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B4%7D%7B52%7D%3D0.076)
The probability is 7.6%
b) On the first 100 positive integers, there are 50 odd integer numbers. Then you have:
![P=\frac{50}{100}=0.5](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B50%7D%7B100%7D%3D0.5)
The probability of getting an odd number is 50%
c) From a total of 365 day in the year, May has 31 day. Then you have:
![P=\frac{31}{365}=0.084](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B31%7D%7B365%7D%3D0.084)
The probability is 8.4%
d) In this case you have two events. To get an odd number with the sum of the number of two dices you need and odd number in one dice and a pair number in the other dice.
The probability is the product of the occurrence of both events. The probability for an odd number is 1/2 and for a pair number is 1/2.
![P=P_{odd}P_{pair}=(\frac{1}{2})(\frac{1}{2})=\frac{1}{4}=0.25](https://tex.z-dn.net/?f=P%3DP_%7Bodd%7DP_%7Bpair%7D%3D%28%5Cfrac%7B1%7D%7B2%7D%29%28%5Cfrac%7B1%7D%7B2%7D%29%3D%5Cfrac%7B1%7D%7B4%7D%3D0.25)
The probability is 25%
e) To obtain Head 6 times in a row, the probability is:
![P=\frac{1}{2}*\frac{1}{2}*\frac{1}{2}*\frac{1}{2}*\frac{1}{2}*\frac{1}{2}=0.00024](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B1%7D%7B2%7D%2A%5Cfrac%7B1%7D%7B2%7D%2A%5Cfrac%7B1%7D%7B2%7D%2A%5Cfrac%7B1%7D%7B2%7D%2A%5Cfrac%7B1%7D%7B2%7D%2A%5Cfrac%7B1%7D%7B2%7D%3D0.00024)
Probability of 0.024%
f) To get Head 4 times from 5 flights, you first calculate the probability for 1 head in five flips:
![P=(\frac{1}{2})^5=\frac{1}{32}](https://tex.z-dn.net/?f=P%3D%28%5Cfrac%7B1%7D%7B2%7D%29%5E5%3D%5Cfrac%7B1%7D%7B32%7D)
There are 5 forms of getting 4 Heads for 5 flips, then you have:
![P=5(\frac{1}{32})=\frac{5}{32}=0.156](https://tex.z-dn.net/?f=P%3D5%28%5Cfrac%7B1%7D%7B32%7D%29%3D%5Cfrac%7B5%7D%7B32%7D%3D0.156)
Te probability is 15.6%
Answer:
Output = 8- input
Step-by-step explanation:
The first point is (1,7)
The input is 1 and the output is 7
The lines goes down, so we know that this is subtraction
Output = 8- input
7 = 8-1
Lets check another point
(5,3)
3 = 8-5
This checks
Answer:
187.5
Step-by-step explanation:
Answer:
B(the second one: x to the power of negative 2 multiplied by y, the whole over x to the power of negative 6 multiplied by y to the power of 2.)
Hope this helps
Have a nice day!
Sorry if it wrong :(