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slava [35]
4 years ago
13

Solve. 1. -3(n+1)=3; 2. 2(c-12)=0; 3. 38=-6t-4;

Mathematics
2 answers:
Doss [256]4 years ago
4 0
1.-3n-3=3   2.2c-24 =0    3.42=-6t
   -3n=6          2c=24          42/-6=t
    n=6/-3        c=12             -7=t 
     n=-2
Fiesta28 [93]4 years ago
4 0
1. -3(n + 1) = 3. 
-3n + -3 = 3. 
-3n + -3 + 3 = 3 + 3. 
-3n = 6. 
-3n/-3 = 6/-3. 
n = -2. 

2. 2(c - 12) = 0. 
2c - 24 = 0. 
2c - 24 + 24 = 0 + 24. 
2c = 24. 
2c/2 = 24/2. 
c = 12. 

3. 38 = -6t - 4. 
38 + 4 = -6t - 4 + 4. 
42 = -6t. 
42/-6 = -6t/-6. 
-7 = t. 

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