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Harrizon [31]
2 years ago
6

In an 80/20 mortgage, what is the first mortgage used for?

Mathematics
1 answer:
ludmilkaskok [199]2 years ago
5 0

Answer:

i think its letter B. 20% down payment

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An advertising executive claims that there is a difference in the mean household income for credit cardholders of Visa Gold and
Maslowich

Answer:

Null hypothesis:\mu_{Visa}=\mu_{Mastercard}

Alternative hypothesis:\mu_{Visa} \neq \mu_{Mastercard}

t=\frac{66970-59060}{\sqrt{\frac{9500^2}{11}+\frac{10000^2}{17}}}}=2.108  

p_v =2*P(t_{26}>2.108)=0.0448

Comparing the p value with the significance level given \alpha=0.1 we see that p_v so we can conclude that we can reject the null hypothesis, and a would be a significant difference between the  in the mean household income for credit cardholders of Visa Gold and of MasterCard Gold at 10% of significance .

Step-by-step explanation:

Data given and notation

\bar X_{Visa}=66970 represent the mean for Visa

\bar X_{Mastercard}=59060 represent the mean for the sample Mastercard

s_{Visa}=9500 represent the population standard deviation for Visa

s_{Mastercard}=10000 represent the population standard deviation for Mastercard

n_{Visa}=11 sample size for the group Visa

n_{Mastercard}=17 sample size for the group Mastercard

t would represent the statistic (variable of interest)

\alpha=0.1 significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different, the system of hypothesis would be:

Null hypothesis:\mu_{Visa}=\mu_{Mastercard}

Alternative hypothesis:\mu_{Visa} \neq \mu_{Mastercard}

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

z=\frac{\bar X_{Visa}-\bar X_{Masterdcard}}{\sqrt{\frac{s^2_{Visa}}{n_{Visa}}+\frac{s^2_{Mastercard}}{n_{Mastercard}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

t=\frac{66970-59060}{\sqrt{\frac{9500^2}{11}+\frac{10000^2}{17}}}}=2.108  

What is the p-value for this hypothesis test?

First we need to calculate the degrees of freedom given by:

df= n_{Visa}+n_{Mastercard}-2 = 11+17-2= 26

Since is a bilateral test the p value would be:

p_v =2*P(t_{26}>2.108)=0.0448

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given \alpha=0.1 we see that p_v so we can conclude that we can reject the null hypothesis, and a would be a significant difference between the  in the mean household income for credit cardholders of Visa Gold and of MasterCard Gold at 10% of significance .

4 0
3 years ago
Peter makes $7000 a month plus some money by commission rates. He gets 6% of everything he sells. If peter sold $55000 worth of
tatiyna
He made a total of $10,300 that month
7 0
3 years ago
I will give Brainliest AND a Cookie!
crimeas [40]

Answer:

it might be c not to sure

Step-by-step explanation:

sorry if u get it wrong

3 0
3 years ago
Read 2 more answers
HELP!!!
ella [17]

Answer:

120

Step-by-step explanation:

We are given that the function for the number of students enrolled in a new course is f(x) = 4^{x}-1.

It is asked to find the average increase in the number of students enrolled per hour between 2 to 4 hours.

We know that the average rate of change is given by,

A = \frac{f(x)-f(a)}{x-a},

where f(x)-f(a) is the change in the function as the input value (x-a) changes.

Now, the number of students enrolled at 4 = f(4) = f(x) = 4^{4}-1 = 255 and the number of students enrolled at 2 = f(2) = f(x) = 4^{2}-1 = 15

So, the average increase A=\frac{f(4)-f(2)}{4-2} = A=\frac{255-15}{4-2} = A=\frac{240}{2} = 120.

Hence, the average increase in the number of students enrolled is 120.

3 0
3 years ago
Could someone please help with this
Marizza181 [45]
It is 13 over 31 your welcome
6 0
3 years ago
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