Take a better pic and I might be able too
Answer:
Often, the simplest way to solve "ax2 + bx + c = 0" for the value of x is to factor the quadratic, set each factor equal to zero, and then solve each factor. But sometimes the quadratic is too messy, or it doesn't factor at all, or you just don't feel like factoring. While factoring may not always be successful, the Quadratic Formula can always find the solution.
The Quadratic Formula uses the "a", "b", and "c" from "ax2 + bx + c", where "a", "b", and "c" are just numbers; they are the "numerical coefficients" of the quadratic equation they've given you to solve.
Answer:

Step-by-step explanation:
Given:
For every 1/2 of an hour that the turtle is crawling, he can travel 3/20 of a mile
Question asked:
At what unit rate is the turtle crawling?
Solution:
As here<u> time taken is given</u> and the <u>distance traveled is also given </u>and hence we will apply speed and distance formula to find rate of crawling of turtle.
Time taken by turtle = 
Distance which can be traveled by turtle = 


Therefore, the rate at which the turtle is crawling is 
Answer: 1521
Step-by-step explanation: use the equation pi times radius square. Your radius is always going to be half your diameter so you'll use 22 instead. Then plug that I'm and you should get 1520.53 rounded would be 1521.
Answer:
You could use the polygon area formula OR here's an easier solution
We draw the lines DC and DE
Angle ADC = 120°
Triangle ADC is a 30 60 90 triangle
In such a triangle Line AE = hypotenuse * sq root (3) /2
Line AE = 3 * 0.8660254038 = 2.5980762114
Line DE = 1.5
Area of Triangle ADE = .5 * 1.5 * 2.5980762114 =
1.9485571586 square meters and entire area of Triangle
ABC = 6 * 1.9485571586
which equals 11.6913429513 square meters
Step-by-step explanation: