Answer:
595
Step-by-step explanation:
SOLUTION STEPS
(2.0×10−3)(3.5×10)
Multiply 2 and 10 to get 20.
(20−3)×3.5×10
Subtract 3 from 20 to get 17.
17×3.5×10
Multiply 17 and 3.5 to get 59.5.
59.5×10
Multiply 59.5 and 10 to get 595.
595
20b + 18s < = 150 (thats less then or equal)
Answer:
x = 19, 17
Step-by-step explanation:
(x-18)(x-18)=1
x^2 - 36x + 324=1
x^2 - 36x = -323
x^2 - 36x + 323 = 1
(x-19)(x-17) = 0
x = 19, 17
Answer:
The answer is 15 5/13
Step-by-step explanation:
It's not obvious here, but you're being asked to find a linear equation for the velocity of the car, given two points on the line that represents this velocity.
Find the slope of the line segment that connects the points (3 hr, 51 km/hr) and (5 hr, 59 km/hr). Graph this line. Where does this line intersect the y-axis? Find the y-value; it's your "y-intercept," b.
Now write the equation: velocity = (slope of line)*t + b
The units of measurement of "slope of line" must be "km per hour squared," and those of the "y-intercept" must be "km per hour."
Part B: Start with the y-intercept (calculated above). Plot it on the vertical axis of your graph. Now label the horizontal axis in hours: {0, 1, 2, 3, 4, 5, 6}. Draw a vertical line through t=6 hours. It will intercept both the horiz. axis and the sloping line representing the velocity as a function of time. Show only the part of the graph that extends from t=0 hours to t=6 hours.
