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3 years ago

What is the distance between each pair of points (-3,3),(5,0)

Mathematics

1 answer:

Effectus [21]3 years ago

7 0

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have the points (-3, 3) and (5, 0).

Substitute the coordinates of the points to the formula:

$d=\sqrt{(5-(-3))^2+(0-3)^2}=\sqrt{8^2+(-3)^2}=\sqrt{64+9}=\sqrt{73}$

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The data in the tables below were collected from first year students at a community college. The variable is "number of credit c

Oliga [24]

Solution :

It is given that P(x) is said to be complete or proper probability distribution if it satisfies the following two ways :

1. $P(x) \geq 0$

2. $\sum_z P(x) = 1$

Now consider,

$\sum_z P(x) = 1$

⇒ $P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)=1$

⇒ $0.61+T+0.14+0.01+0.01+0.03=1$

⇒ $0.8+T=1$

⇒ $T=1-0.8$

= 0.2

Therefore, the value of T is 0.2

Thus, option (c) is correct.

7 0

3 years ago

What is the approximate area of a sector given O= 56 degrees with a diameter of 12m?

jeyben [28]

Area of sector is 17.584 meters

Solution:

Given that we have to find the approximate area of a sector given O= 56 degrees with a diameter of 12m

Diameter = 12 m

Radius = Diameter / 2 = 6 m

An angle of 56 degrees is the fraction $\frac{56}{360}$ of the whole rotation

A sector of a circle with a sector angle of 56 degrees is therefore also the fraction $\frac{56}{360}$ of the circle

The area of the sector will therefore also be $\frac{56}{360}$ of the area

$\text{ sector area } = \frac{56}{360} \times \pi r^2\\\\\text{ sector area } = \frac{56}{360} \times 3.14 \times 6^2\\\\\text{ sector area } = 17.584$

Thus area of sector is 17.584 meters

3 0

3 years ago

Type the correct answer in each box.

Mariulka [41]

Answer:

$(x-5)^2+(y+4)^2=100$

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The distance between the center and any point that lie on the circle is equal to the radius

we have the points

(5,-4) and (-3,2)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

substitute the values

$r=\sqrt{(2+4)^{2}+(-3-5)^{2}}$

$r=\sqrt{(6)^{2}+(-8)^{2}}$

$r=\sqrt{100}\ units$

$r=10\ units$

step 2

Find the equation of the circle

we know that

The equation of a circle in standard form is equal to

$(x-h)^2+(y-k)^2=r^2$

where

(h,k) is the center

r is the radius

we have

$(h,k)=(5,-4)\\r=10\ units$

substitute

$(x-5)^2+(y+4)^2=10^2$

$(x-5)^2+(y+4)^2=100$

6 0

3 years ago

PLZ HELP ME !!!! Which expressions below equal a rational number ? Choose ALL that apply !

Yakvenalex [24]

(From top to bottom) wrong, right, right, right, wrong. This is because a irrational*an irrational number is rational, but a rational*an irrational is an irrational number

4 0

3 years ago

Read 2 more answers

What is the approximate perimeter of a rhombus with the diagonals that measure 12 feet and 18 feet

Fynjy0 [20]

Answer:

The perimeter of a rhombus with diagonals of 12 feet and 18 feet would be 60 feet.

Step-by-step explanation:

Perimeter of a rhombus: S1 + S2 + S3 + S4 = answer. (S stands for side.)

12 ft. + 18 ft. + 12 ft. + 18 ft. = 60 ft.

7 0

3 years ago