<em><u>your </u></em><em><u>question</u></em><em><u>:</u></em><em><u> </u></em>
A pair of equations is shown below:
y = 7x − 9
y = 3x − 1
Part A: In your own words, explain how you can solve the pair of equations graphically. Write the slope and y-intercept for each equation that you will plot on the graph to solve the equations. (6 points) YOU HAVE ALREADY ANSWERED
Part B: What is the solution to the pair of equations? (4 points)
<em><u>answer:</u></em><em><u> </u></em>
<em>t</em><em>he </em><em>solution </em><em>to </em><em>the </em><em>pair </em><em>of </em><em>equations </em><em>would </em><em>be </em>
(2,5)
<em><u>how </u></em><em><u>do </u></em><em><u>we </u></em><em><u>get </u></em><em><u>this</u></em><em><u>?</u></em>
<em> </em><em>you </em><em>put </em><em>both </em><em>equations </em><em>in </em><em>a </em><em>desmos </em><em>graphing </em><em>calculator</em><em> </em>
<em>hope </em><em>this </em><em>helps,</em><em> </em><em>have </em><em>a </em><em>great </em><em>night </em><em>:</em><em>)</em><em> </em>
Answer:
Option B.
Step-by-step explanation:
Cost of game = $5.00
If they draw a face card, they win $10.00 (i.e. they get their $5.00 back and get an extra $5.00).
Winning amount = $5
Number of face cards = 12
Probability of getting a face card =
If they draw an ace, they win $20.00 (i.e. they get their $5.00 back and get an extra $15.00).
Winning amount = $15
Number of ace = 4
Probability of getting an ace =
Any other draw they lose their money.
Number of other card (Exclude ace and face cards) = 52-4-12=36
Probability of getting other cards =
The expected money value playing this game is
E(x) = 5 × P(face cards) + 15 × P(Ace) - 5 × P(Other cards)
The expected money value playing this game is -$1.15
Therefore, the correct option is B.
Answer:
The probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.
Step-by-step explanation:
Let the random variable <em>X</em> represent the time a child spends waiting at for the bus as a school bus stop.
The random variable <em>X</em> is exponentially distributed with mean 7 minutes.
Then the parameter of the distribution is,
.
The probability density function of <em>X</em> is:
Compute the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning as follows:
![=\int\limits^{9}_{6} {\frac{1}{7}\cdot e^{-\frac{1}{7} \cdot x}} \, dx \\\\=\frac{1}{7}\cdot \int\limits^{9}_{6} {e^{-\frac{1}{7} \cdot x}} \, dx \\\\=[-e^{-\frac{1}{7} \cdot x}]^{9}_{6}\\\\=e^{-\frac{1}{7} \cdot 6}-e^{-\frac{1}{7} \cdot 9}\\\\=0.424373-0.276453\\\\=0.14792\\\\\approx 0.148](https://tex.z-dn.net/?f=%3D%5Cint%5Climits%5E%7B9%7D_%7B6%7D%20%7B%5Cfrac%7B1%7D%7B7%7D%5Ccdot%20e%5E%7B-%5Cfrac%7B1%7D%7B7%7D%20%5Ccdot%20x%7D%7D%20%5C%2C%20dx%20%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B7%7D%5Ccdot%20%5Cint%5Climits%5E%7B9%7D_%7B6%7D%20%7Be%5E%7B-%5Cfrac%7B1%7D%7B7%7D%20%5Ccdot%20x%7D%7D%20%5C%2C%20dx%20%5C%5C%5C%5C%3D%5B-e%5E%7B-%5Cfrac%7B1%7D%7B7%7D%20%5Ccdot%20x%7D%5D%5E%7B9%7D_%7B6%7D%5C%5C%5C%5C%3De%5E%7B-%5Cfrac%7B1%7D%7B7%7D%20%5Ccdot%206%7D-e%5E%7B-%5Cfrac%7B1%7D%7B7%7D%20%5Ccdot%209%7D%5C%5C%5C%5C%3D0.424373-0.276453%5C%5C%5C%5C%3D0.14792%5C%5C%5C%5C%5Capprox%200.148)
Thus, the probability that the child must wait between 6 and 9 minutes on the bus stop on a given morning is 0.148.
Answer:
Increased.
Step-by-step explanation:
In March 2007, the unemployment rate was 4.4 percent. In August 2008 was 6.1 percent. We need to remember that the unemployment rate equals the number of unemployed people divided by the people in the labor force.
Now, if we consider that the labor force remained constant during this period of time (according to the problem) then this would mean that the number of unemployed people actually increased during this period of 17 months.
Answer:
23 stones are going to be needed
Step-by-step explanation:
