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artcher [175]
3 years ago
14

Many families in California are using backyard structures for home offices, art studios, and hobby areas as well as for addition

al storage. Suppose that the mean price for a customized wooden, shingled backyard structure is $3,200. Assume that the standard deviation is $1,200. (a) What is the z-score for a backyard structure costing $2,300
Mathematics
1 answer:
Natalija [7]3 years ago
7 0

Answer:

-0.75

Step-by-step explanation:

To get the z score we have to use this formula

Z = X-mean/standard deviation

X = 2300

Mean = 3200

The standard deviation = 1200

When we plug these values into the z formula above, we have:

2300-3200/1200

= -900/1200

= -0.75

the z-score for a backyard structure costing $2,300 is therefore -0.75

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True or false the reciprocal of 5 is 1/5<br>シ​
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Answer:

True

Step-by-step explanation:

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A store has been selling 100 Blu-ray disc players a week at $600 each. A market survey indicates that for each $40 rebate offere
Sav [38]

Answer:

<em>The rebate should be $220</em>

Step-by-step explanation:

<u>Demand Curve</u>

It's the relationship between price (P) and quantity (Q) demanded a certain product or service.

(a) We need to find the function that relates both magnitudes assuming a linear equation. The equation of a line can be found with the point-point formula:

\displaystyle Q-Q_1=\frac{Q_2-Q_1}{P_2-P_1}(P-P_1)

Two sets of data are given: 100 Blu-ray disc players are sold a week at $600 each. The ordered pair for this condition is (P,Q)=(600,100).

The other point comes from the market survey: The number of units sold will increase by 80 (100+80=180) when the price goes down $40 (600-40=560). The new point is (P,Q)=(560,180)

We set up the equation of the demand

\displaystyle Q-100=\frac{180-100}{560-600}(P-560)

Rearranging

-40Q+4000=80P-44800

Or

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Simplifying

2P+Q=1120

(b) The revenue function is Q times the price

R=Q.P

Solving the equation of the demand for P

\displaystyle P=\frac{1120-Q}{2}

Thus, the revenue is

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\displaystyle R=\frac{1120Q-Q^2}{2}

(c) To find the optimum value of the revenue, we take the derivative of R and equate to 0

\displaystyle R'=\frac{1120-2Q}{2}=560-Q=0

Solving

Q=560 units a week

For which the revenue is

\displaystyle R=\frac{1120(560)-560^2}{2}

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And the price is

\displaystyle P=\frac{1120-560}{2}=280

P=\$280

The rebate should be $600-$280=$220

4 0
3 years ago
Could Someone help me, thank you so much!
maxonik [38]

Answer: Answer choice A

Step-by-step explanation:

Because 2 has 20 copies 4 has 40 so we can only assume that 6 will follow the pattern and be 60.

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anyanavicka [17]
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