Answer:
Ok, we have a system of equations:
6*x + 3*y = 6*x*y
2*x + 4*y = 5*x*y
First, we want to isolate one of the variables,
As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:
(6*x + 3*y)/(2*x + 4*y) = 6/5
now we isolate one off the variables:
6*x + 3*y = (6/5)*(2*x + 4*y) = (12/5)*x + (24/5)*y
x*(6 - 12/5) = y*(24/5 - 3)
x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y
Now we can replace it in the first equation:
6*x + 3*y = 6*x*y
6*(0.5*y) + 3*y = 6*(0.5*y)*y
3*y + 3*y = 3*y^2
3*y^2 - 6*y = 0
Now we can find the solutions of that quadratic equation as:
So we have two solutions
y = 0
y = 2.
Suppose that we select the solution y = 0
Then, using one of the equations we can find the value of x:
2*x + 4*0 = 5*x*0
2*x = 0
x = 0
(0, 0) is a solution
if we select the other solution, y = 2.
2*x + 4*2 = 5*x*2
2*x + 8 = 10*x
8 = (10 - 2)*x = 8x
x = 1.
(1, 2) is other solution
The graph of y = (-3x)^2 is much narrower than it's original graph, but still keeps all of the other properties of it's parent parable y = x^2. The new graph's with is that of the original parabola's with divided by 3.
Answer: 
Step-by-step explanation:
Given : In a sociology class there are 14 sociology majors and 11 non-sociology majors.
Total students = 14+11=25
Number of students are randomly selected = 3
Then, the number of ways to select 3 students from 25 students :-
Number of ways to select at least 2 of the 3 students re non-sociology majors :-
The probability that at least 2 of the 3 students selected are non-sociology majors will be :-
Owes more than 1425
owe>1425
owed musbe be equal to how much he paid back
paid back 210
and 153 per month is paid back (represent number of months by x)
so
owe=210+152x
210+153x>1425
153x+210>1425
Don't know if this is right or if it helps but
The given equations are y= 6x^2+1 and y=x^2+4
Both the equations equal y so we can make them equal
6x^2+1=x^2+4
To bring x term on one side we subtract x^2 both sides
6x^2-x^2+1=4
5x^2+1=4
To isolate x term we subtract 1 both sides
5x^2=4-1
5x^2=3
Dividing by 5 both sides
X^2=3/5
Taking root of both sides we have:
X=±√⅗
Substituting x value to find y
When x=+√⅗=0.7745
Y= 6x^2+1
Y=6(3/5)+1
Y= 18/5+1
Y=23/5 =4.6
When x= -√⅗=-0.7745
Y= 6(3/5)+1
Y=23/5=4.6
Point of intersections are ( 0.7745,4.6) and (-0.7745,4.6)
