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Pavel [41]
3 years ago
7

identify the vertex of the following function and state of it is a minimum or maximum f(x)= 2(x-3)2+ 2

Mathematics
1 answer:
Alinara [238K]3 years ago
6 0

Answer:

vertex = (3, 2)

minimum

Step-by-step explanation:

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kondaur [170]

Answer:

x + 2, x ≠ -2

Step-by-step explanation:

Note that F(x) = x^2 + 4x + 4 factors into (x + 2)^2, and that we are dividing this by g(x) = x + 2.  The quotient is x + 2, which in this problem has been named h(x).  

The quotient (f/g)(x) is therefore x + 2 EXCEPT that this is not defined at x = -2, because the denominator, x + 2, will be zero there, undefined.

8 0
3 years ago
Write an equation of a line in slope intercept form that is perpendicular to y = -4x -2 and passes through the point (-16, -11).
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Y = -4x - 2
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a = -4, b = 0, c = -2
m = -a/b
m = -(-4)/(-2)
m = 4/(-2)
m = -2

y-yo = m(x-xo)
y-(-11) = -2[x-(-16)]
y+11 = -2(x+16)
y+11 = -2x-32
2x+y+11+32 = 0
2x+y+43 = 0

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