. A lizard needs to stay a safe distance from a cactus. The diameter of the cactus is 14 inches. If the lizard is 8 inches from
a point of tangency, find the direct distance between the lizard and the cactus (x). If necessary, round to the hundredths place.. . A.. x = 3.63 in.. B.. x = 4.57 in.. C.. x = 7.26 in.. D.. x = 17.63 in..
We will use Pythagorean theorem: x - The direct distance between the lizard and the cactus; r = 7 - radius of the cactus; x + 7 - the distance between the lizard and the center of the cactus: ( x + 7 )² = 7² + 8² ( x + 7)² = 49 + 64 ( x + 7 )² = 113 x + 7 = √ 113 x + 7 = 10.63 x = 10.63 - 7 x = 3.63 Answer: A)
Using the equation: <span>8^2 = x(x+14) </span>64=x^2 +14x <span>x^2 +14x-64=0 </span>using quadratic formula : we get 2 values: 3.63 and -17.63 negative is not possible so our answer is 3.63
The area of a square is its side length squared. So the side length of the square squared is 42, so the side length of the square is sqrt(42). The perimeter of the square is 4 times the side length, or 4sqrt(42), which is approximately 25.92.
