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lakkis [162]
3 years ago
15

. A lizard needs to stay a safe distance from a cactus. The diameter of the cactus is 14 inches. If the lizard is 8 inches from

a point of tangency, find the direct distance between the lizard and the cactus (x). If necessary, round to the hundredths place.. . A.. x = 3.63 in.. B.. x = 4.57 in.. C.. x = 7.26 in.. D.. x = 17.63 in..
Mathematics
2 answers:
Elanso [62]3 years ago
7 0
We will use Pythagorean theorem:
x - The direct distance between the lizard and the cactus;
r = 7 - radius of the cactus;
x + 7 - the distance between the lizard and the center of the cactus:
( x + 7 )² = 7²  + 8²
( x + 7)² = 49 + 64
( x + 7 )² = 113
x + 7 = √ 113 
x + 7 = 10.63
x = 10.63 - 7
x = 3.63
Answer: A)  
pickupchik [31]3 years ago
6 0
Using the equation:
<span>8^2 = x(x+14)
</span>64=x^2 +14x
<span>x^2 +14x-64=0
</span>using quadratic formula :
we get 2 values:
3.63 and -17.63
negative is not possible so our answer is 3.63
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the area of a rectangle is 85 square feet. the length is 12 feet longer than the width. find the length and width of the wall
Fed [463]
Formula for area of rectangle:
A=L x w
Here A=85 square ft
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Put values in formula.
85=(w+12)w
85=w^2+12w
Subtract 85 from both sides
w^2+12w-85=0
Factorise the equation.
(w-5)(w+17)=0
w=5 and w=-17
Ignore the negative value of width.
Width, w= 5 ft  and Length, L=12+5=17 ft

Answer: Width=5 ft and Length=17 ft
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