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2 years ago

What is the solution to this system of linear equations?

Mathematics

2 answers:

kvasek [131]2 years ago

7 0

Answer:

The correct answer is D. (-1,3)

QveST [7]2 years ago

7 0

Answer:

The answer would be D (-1, 3)

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Please help with this question,i am going to add a picture to it.

laiz [17]

Answer:

I'd love to answer your question!!!

It looks like you forgot to attach the picture or the connection failed D:

Could you post the question again?

Thx!

Sahkfam

5 0

3 years ago

Simplify 2/5k - 3/5 + 1/10k

malfutka [58]

The answer to this question, if I'm correct would be:

1/2k - 3/5

I hope I could help (:

6 0

3 years ago

Read 2 more answers

Sammy has x flavors of candies with which to make goody bags for Frank's birthday party. Sammy tosses out y flavors, because he

harkovskaia [24]

Answer:

$^{(x-y)}C_{10}=\frac{(x-y)!}{10! \times (x-y-10)!}$

Step-by-step explanation:

Total flavors Sammy initially had = x

Number of flavors Sammy throw away = y

After throwing away y flavors, the number of flavors Sammy will be left with = x - y

He needs to make 10-flavor bags from these (x - y) flavors. In order words he needs to chose 10 flavors for each bag from(x - y) flavors. The order of selection is not important here, so this is a problem of combinations. Also since we have to make selections or small groups, this also indicates that we have to use combinations.

So we need to make combinations of 10 flavors from a total of (x - y) flavors. This can be represented as $^{(x-y)}C_{10}$

The formula for combinations is:

$^{n}C_{r}=\frac{n!}{r!(n-r)!}$

Using the values in this formula, we get:

$^{(x-y)}C_{10}=\frac{(x-y)!}{10! \times (x-y-10)!}$

7 0

2 years ago

at a local restaurant the health inspector visits every 7 Days and the fire inspector visits every 12 days make a table for the

seraphim [82]

Day Inspector

7 H

12 F

14 H

21 H

24 F

28 H

35 H

36 F

42 H

48 F

49 H

56 H

60 F

63 H

70 H

72 F

77 H

84 H, F

6 0

3 years ago

Help me with this 1,2,3. For each sequence, Determine with whether it appears to be arithmetic If it does find a common differen

pshichka [43]

Problem 1

<h3>Answer: Arithmetic, common difference = -4</h3>

-------------------

Explanation:

Pick any term of the sequence, and subtract off the previous term to find that,

term2 - term1 = -12 - (-8) = -12 + 8 = -4
term3 - term2 = -16 - (-12) = -16 + 12 = -4
term4 - term3 = -20 - (-16) = -20 + 16 = -4

Each time we get the same result, so that means we have an arithmetic sequence with common difference -4

This indicates that adding -4 to each term, or subtracting 4 from each term, will generate the next one.

Eg: term2 = term1 - 4 = -8-4 = -12.

==========================================================

Problem 2

<h3>Answer: Arithmetic, common difference = 5</h3>

-------------------

Explanation:

Similar to problem 1, this sequence is also arithmetic because we add on 5 to each term to get the next one

-6+5 = -1
-1+5 = 4
4+5 = 9

Or you could subtract adjacent terms as done in problem 1, to find that the common difference is 5.

==========================================================

Problem 3

<h3>Answer: Not arithmetic</h3>

-------------------

Explanation:

Unlike the previous two problems, this sequence is not arithmetic.

We can see that

term2 - term1 = 12 - 3 = 9
term3 - term2 = 48 - 12 = 36

The gaps of 9 and 36 aren't the same. We need the same common difference between any adjacent terms to have an arithmetic sequence.

This sequence is instead geometric because

term2/term1 = 12/3 = 4
term3/term2 = 48/12 = 4
term4/term3 = 192/48 = 4

Each quotient is 4, showing the common ratio is 4. To find the next term, we multiply the current term by 4. So the next term after 192 would be 4*192 = 768, then 4*768 = 3072 is next, and so on.

3 0

3 years ago