The standard equation of a circle is
(x-h)^2 + (y-k)^2 = r^2
where the center is at point (h,k)
From the statement of the problem, it is already established that h = 2 and k = -5. What we have to determine is the value of r. This could be calculated by calculating the distance between the center and point (-2,10). The formula would be
r = square root [(x1-x2)^2 + (y1-y2)^2)]
r = square root [(2--2)^2 + (-5-10)^2)]
r = square root (241)
r^2 = 241
Thus, the equation of the circle is
Answer:
The correct answer is False
We integrate the given equation such that,
integral of g(x) = (5/3)x³ - 9x² + 35x
Substituting,
x = 13
integral of g(x) = (5/3)(13³) - 9(13)² + 35(13)
= 2595.67
and, x = 0
integral of g(x) = 0
The area is 2595.67 - 0 = 2595.67
For the second part,
x = 1
integral of g(x) = (5/3)(1)³ - 9(1)² + 35(1)
= 27.67
Area under the curve between x = 0 and x = 1 is 27.67
The difference between the two areas is,
2595.67 - 27.67 = 2568.0
Answer: 2568.0 units squared
Answer:
C. 24 ft.
Step-by-step explanation:
There is a right triangle which can be drawn in side the pyramid with height h, hypotenuse 25 ft and bas = 1/2 * 14 = 7.
So using Pythagoras:
25^2 = h^2 + 7^2
h^2 = 25^2 - 7^2
h^2 = 576
h = √576 = 24 ft.
Answer:
x = 34/21
Step-by-step explanation:
- 3 = 7/2 (3x-4)
- 3 = (21/2)x - 28/2
- 3 = (21/2)x - 14
- (21/2)x = 17
- 21x = 34
- x = 34/21