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mixer [17]
3 years ago
12

In order to estimate the mean amount of time computer users spend on the internet each month. How many computer users must be su

rveyed in order to be 95% confident that your sample mean is within 10 minutes of the population mean? Assume that the standard deviation of the population of monthly time spent on the internet is 211 min. What is a major obstable to getting a good estimate of the population mean? Use technology to find the estimated minimum required sample size.
The minimum sample size required is ___ computer users.

What is a major obstacle to getting a good estimate of the population mean?
a) There may not be 1,809 computer users to survey
b) It is difficult to precisely measure the amount of time spent on the internet,invidating some data values
c) The data does not provide information on what the computers users did while on the internet
d) There are no obstacles to getting a good estimate of the population mean
Mathematics
1 answer:
evablogger [386]3 years ago
4 0

Answer:

Step-by-step explanation:

Given that confidence level is 95% and sample mean is within 10 minutes of the population mean.  i.e. margin of error = 10

Std deviation of population= 211 minutes

Margin of error = Z critical * std error

Std error = sigma/sq rt n = \frac{211}{\sqrt{n} }

Hence we have

\frac{211}{\sqrt{n} }\frac{211}{\sqrt{n} }*1.9641.356\\n>1710

The minimum sample size is 1710

a) There may not be 1,809 computer users to survey

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Write these numbers in order from least to greatest. (You will have to change the fractions to equivalent decimals to place them
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0.1201<0.121<0.131<0.137<0.139<0.14<0.1401<0.141<0.147<0.149

Step-by-step explanation:

OK let's see the numbers:

0.131,0.141,0.121,0.139,0.1201,0.1401,0.14,0.147,0.149,0.137​

First off, we find the smallest number, We highlight the ones that have 1 for hundredth digit, looks like there's none!, try 2 for the hundredth digit:

0.131,0.141,0.121,0.139,0.1201,0.1401,0.14,0.147,0.149,0.137​

There's two! 0.1201 is smaller than 0.121, so 0.1201 one is smallest followed by 0.121.

What we already have:

0.1201<0.121

Then we find the decimals that have 3 for hundredth digit.

0.131,0.141,0.121,0.139,0.1201,0.1401,0.14,0.147,0.149,0.137​

There's three!

0.131 is smaller than 0.137 and both of them are smaller than 0.139.

What we already have:

0.1201<0.121<0.131<0.137<0.139

We now find the decimals that have 4 for hundredth digit.

0.131,0.141,0.121,0.139,0.1201,0.1401,0.14,0.147,0.149,0.137​

There's five!

We can see that 0.14 is smaller than 0.1401 is smaller than 0.141 is smaller than 0.147 is smaller than 0.149.

What we already have:

0.1201<0.121<0.131<0.137<0.139<0.14<0.1401<0.141<0.147<0.149

And this is the answer:

0.1201<0.121<0.131<0.137<0.139<0.14<0.1401<0.141<0.147<0.149

Have a nice day! :)

-Vana

8 0
3 years ago
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