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Bumek [7]
2 years ago
6

I WILL THANK YOU THE QUESTION IS THE PHOTO! Pls answer ASAP IM GIVING 40 POINTS!!!

Mathematics
1 answer:
yarga [219]2 years ago
7 0

Answer:

C or D

Step-by-step explanation:

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What is the following product? 3^sqr4 * sqr3​
Nina [5.8K]

Answer:

9sqrt3

Step-by-step explanation:

This is an order of operations question.

First, simply the exponent, which gives you 3^2*sqrt3

Next, 3^2=9, giving the final answer of 9sqrt3.

3 0
3 years ago
Please HELP ASAP PLEASE?????!!!!
Akimi4 [234]

Answer:

-1

Step-by-step explanation:

Any number less than -2 (ex -3, -4, -5) are less than -2

3 0
2 years ago
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A recipe for sparkling grape juice calls for 1 1\2 quarts of water and 3\4 quarts of grape juice. How much sparkling water would
WITCHER [35]

Answer:

You will need 18

Step-by-step explanation:

4 0
2 years ago
Help!! Asappp!! please​
kotykmax [81]

Answer:

C

Step-by-step explanation:

you add 15 and 10 witch gets you 25 and then you add 3 for the students that don't play either witch gets you 28 and then subtract 28 from 32, or just count up from 28 to 32 but you get the same answer.

4 0
2 years ago
Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE​
eduard

Answer:

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

Step-by-step explanation:

Given the matrices

A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}

B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}

Calculating AB:

\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}

Multiply the rows of the first matrix by the columns of the second matrix

                                   =\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}

                                   =\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}

Hence,

\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}

Therefore,

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

5 0
2 years ago
Read 2 more answers
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