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storchak [24]
4 years ago
15

Ayudaaaaa, Instale el software equivocado a mi tv westinghause con placa tp.Ms338.Pb801 y ahora queda en negro, ¿Cómo lo puedo s

olucionar?. Ya intente instalarle otro sofware, pero ya no me sale ni la pantalla azul que indica que se esta instalando.
Computers and Technology
1 answer:
Alona [7]4 years ago
6 0

Answer:

what is your question soo that i can help u ????????

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Que relacion tiene Las palabras: fermentacion-vino y clonacion- dolly​
rjkz [21]

Answer:

Al final, la hembra adulta da a luz a un animal que tiene la misma composición genética que el animal que donó la célula somática. A esta cría se le conoce como clon. La clonación reproductiva podría requerir el uso de una madre sustituta para hacer posible el desarrollo del embrión clonado, tal como fue el caso del más famoso.

Explanation:

4 0
3 years ago
Integers and booleans. Write a program RightTriangle that takes three int command-line arguments and determines whether they con
icang [17]

Answer:

<em>The programming language is not stated;</em>

<em>I'll answer using C++</em>

#include<iostream>

#include<cmath>

using namespace std;

int main()

{

int side1, side2, side3;

cout<<"Enter the three sides of the triangle: "<<endl;

cin>>side1>>side2>>side3;

if(side1<=0 || side2 <= 0 || side3 <= 0) {

 cout<<"Invalid Inputs";

}

else {

 if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else {

  cout<<"Not Right Angled";

 }

}

return 0;

}

Explanation:

The following line declares the three variables

int side1, side2, side3;

The next line prompts user for input of the three sides

cout<<"Enter the three sides of the triangle: "<<endl;

The next line gets user input

cin>>side1>>side2>>side3;

The following if condition checks if any of user input is negative or 0

<em> if(side1<=0 || side2 <= 0 || side3 <= 0) { </em>

<em>  cout<<"Invalid Inputs"; </em>

<em> } </em>

If otherwise

else {

The following if condition assumes that side1 is the largest and test using Pythagoras Theorem

<em>if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

The following if condition assumes that side2 is the largest and test using Pythagoras Theorem

<em>  else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

The following if condition assumes that side3 is the largest and test using Pythagoras Theorem

<em>  else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

If none of the above conditions is true, then the triangle is not a right angles triangle

<em>  else { </em>

<em>   cout<<"Not Right Angled"; </em>

<em>  } </em>

}

return 0;

Download cpp
4 0
4 years ago
What is a Network?
navik [9.2K]

Answer:

Letter A

Explanation:

Think about it like a web

6 0
3 years ago
Read 2 more answers
Convert decimal number into binary numbers (265)10<br>​
Ksenya-84 [330]

Answer:

HELLOOOO

Alr lets start with steps by dividing by 2 again and againn..

265 / 2 = 132 ( rem = 1 )

132 / 2 = 66 ( rem = 0 )

66/2 = 33 ( rem = 0 )

33/2 = 16 ( rem = 1 )

16/2 = 8 ( rem = 0 )

8/2 = 4 ( rem = 0 )

4/2 = 2 ( rem = 0 )

2/2 = 1 ( rem = 0 )

1/2 = 0 ( rem = 1 )

now write all the remainders from bottom to up

100001001

is ur ans :)))

7 0
3 years ago
Which of the following are associated with Public Key encryption? (Select all that apply.) Question 2 options: a) Asymmetric key
tatiyna

Answer:

A- ASYMMETRIC KEYS

Explanation:

Assymmetric keys are public keys that are use for encryption. They are public keys which may be disseminated or share widely, they are usually know by everyone. The keys come in pairs in which what one key encrypts, only the other can decrypt.

Asymmetric keys allows someone to send their public key in an open and insecure channel.

3 0
3 years ago
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