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zheka24 [161]
2 years ago
5

Write the word sentence as an equation. Then solve the equation.

Mathematics
1 answer:
Nana76 [90]2 years ago
7 0

Answer:

see below

Step-by-step explanation:

9 is the difference of a number n and 7.

Let's break this down.

"is" represents the equal sign.

"the difference" represents subtraction.

9 = n - 7

Now let's solve the equation.

9 = n - 7

Add 7 to both sides.

16 = n

Hope this helps!

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The number being multiplies Its called the factor so.. factor ×factor= product. Product is the answer of the multiplication problem
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Three corners of a city bloc is located at (2,2) (2,-4) (-5,-4) on a coordinate plane what are the coordinates of the fourth cor
AleksandrR [38]

Answer:

(-5, 2)

Step-by-step explanation:

Three corners of a rectangular city block are located at (2,2), (2,-4) and (-5,-4) on a coordinate plane. What are the coordinates of the fourth Coordinate?

Solution:

A rectangle is a quadrilateral (has four sides and four angles) in which opposite sides are equal and parallel. Also, all the angles are at 90 degrees.

Since the city block is rectangular in shape, therefore the fourth coordinate would have the same y coordinate as the point (2, 2) and it would also have the same x coordinate as (-5, -4).

Hence the fourth coordinate is (-5, 2)

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2 years ago
What is the difference between an expression and an equation? Provide an example of each.
Tcecarenko [31]

Answer:

Expressions are not meant to be solved, they are more so to be evaluated and explained.. a visual differenceis that there is no equal sign or answer written, an equation is solved and has an equal answer. EXPR: (2 x 13) + 9 EQU: (19 x 12) + 3= 231

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Use the alternative form of the derivative to find the derivative at x = c (if it exists). (If the derivative does not exist at
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Answer:

The derivative of the function does not exist.

Step-by-step explanation:

The alternative form of a derivative is given by:

f'(c)= \lim_{x \to c} \dfrac{f(x)-f(c)}{x-c}

Our function is defined as:

h(x)=|x+8|

i.e.  h(x)=   -(x+8) when x+8<0

           and   x+8  when x+8≥0

i.e. h(x)=  -x-8   when x<-8

      and   x+8  when x≥-8

Hence now we find the derivative of the function at c=-8

i.e. we need to find the Left hand derivative (L.H.D.) and Right hand derivative (R.H.D) of the function.

The L.H.D at a point 'a' is calculated as:

\lim_{x \to a^-} \dfrac{f(x)-f(a)}{x-a}\\\\=\lim_{h \to0} \dfrac{f(a-h)-f(a)}{a-h-a}= \lim_{h\to 0}  \dfrac{f(a-h)-f(a)}{-h}

Similarly R.H.D is given by:

\lim_{x \to a^+} \dfrac{f(x)-f(a)}{x+a}\\\\=\lim_{h \to 0} \dfrac{f(a+h)-f(a)}{a+h-a}= \lim_{h\to 0} \dfrac{f(a+h)-f(a)}{h}

Now for L.H.D we have to use the function h(x) =-x-8

and for R.H.D. we have to use the function h(x)=x+8

L.H.D.

we have a=-8

\lim_{x \to (-8)^-} \dfrac{h(x)-h(-8)}{x-(-8)}\\\\= \lim_{h \to0} \dfrac{h(-8-h)-h(-8)}{-8-h-(-8)}= \lim_{h\to 0} \dfrac{h(-8-h)-h(-8)}{-h}

= \lim_{h \to 0} \dfrac{8+h-8-0}{-h}= \lim_{h \to 0}\dfrac{h}{-h}=-1

similarly for R.H.D.

\lim_{x \to (-8)^+} \dfrac{h(x)-h(-8)}{x-(-8)}\\\\=\lim_{h \to 0} \dfrac{h(-8+h)-h(-8)}{-8+h-(-8)}= \lim_{h\to 0} \dfrac{h(-8+h)-h(-8)}{h}

\lim_{h \to 0} \dfrac{-8+h+8-0}{h}=\lim_{h \to 0}\dfrac{h}{h}=1

Now as L.H.D≠R.H.D.

Hence, the function is not differentiable.



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